Hi friends, I am having 2 files, I just want to compare 2 files each containing 2 columns 1st column is lat, and 2nd column is long, if anyone can understand below logic please help me in writing script with awk.. here each field of file2 needs to be compared with std_file
Hello friends,
I have a problem in printing an array..
Example if my array line contains 4 elements like following
line=0002 , line=202200, line=200002, line= 300313
Now one = sprintf line line line line will concatenate my whole array to one.
But I am not sure about the... (7 Replies)
Hello Friends,
I have a txt file like below
//*Init Start
Reg(read,12'h42E,16'h0000);
Nop(5628.5);
//*Init End
//*Main Start
Reg(read,12'h42E,16'h0000);
Nop(5628.5);
//*Main End
I want to calculate the values between //* Init Start & //* Init End
And //*Main Start & //*Main... (5 Replies)
Hi Friends,
I got stuck where to start with ..
I ve a input file like below. where I want to compare write data with my read data .. The problem is that the read data should be compared with the lastest write data on that address.
Note- Both write data & read data are in the same... (8 Replies)
I want to print lines that have "IND" or "ind" or nothing in field 2 or 3
file:
output needed:
Code i wrote:
nawk -F"," '{if(tolower($2||$3) ~"ind"||"")print}' file
Help is appreciated (3 Replies)
In one data file i have values like this
a b c 1 2
e f g 2 3
i j k 3 5
I need to sum up the last 2 columns and make a data file...How i can do that.
a b c 1 2
e f g 2 3
i j k 3 5... (8 Replies)
I have task to find out the min,max, average value of each service for example i searched for " StatementService "
$awk '/VST.*StatementService:/{print $3,$4,$19,$22,$25}' performance.log > smp.log
$cat smp.log
amexgtv VST: : StatementService:1860 StatementService:getCardReference:0... (3 Replies)
Hi,
My file has 2 fields and millions of lines.
variableStep chrom=Uextra span=25
201 0.5952
226 0.330693
251 0.121004
276 0.0736858
301 0.0646982
326 0.0736858
401 0.2952
426 0.230693
451 0.221004
476 0.2736858
Each field either has a... (6 Replies)
I am trying to check my logic on a long awk i'm using. I have about 30 checks that I built into an awk and I "believe" I did this right, but I could be wrong.
awk -F\| '
$9 !~ /\/*{1,}*/
$9 ~ /\(-{4}, {2,3}/
$9 ~ /\({6}, {2,3}\)/
$9 ~ /\(\+{5}, {2,3}\)/
$9 ~ /\(\+\+{4}, {2,3}\)/
$9 ~... (8 Replies)
Discussion started by: dagamier
8 Replies
LEARN ABOUT SUSE
mrtg-logfile
MRTG-LOGFILE(1) mrtg MRTG-LOGFILE(1)NAME
mrtg-logfile - description of the mrtg-2 logfile format
SYNOPSIS
This document provides a description of the contents of the mrtg-2 logfile.
OVERVIEW
The logfile consists of two main sections.
The first Line
It stores the traffic counters from the most recent run of mrtg.
The rest of the File
Stores past traffic rate averates and maxima at increassing intervals.
The first number on each line is a unix time stamp. It represents the number of seconds since 1970.
DETAILS
The first Line
The first line has 3 numbers which are:
A (1st column)
A timestamp of when MRTG last ran for this interface. The timestamp is the number of non-skip seconds passed since the standard UNIX
"epoch" of midnight on 1st of January 1970 GMT.
B (2nd column)
The "incoming bytes counter" value.
C (3rd column)
The "outgoing bytes counter" value.
The rest of the File
The second and remaining lines of the file contains 5 numbers which are:
A (1st column)
The Unix timestamp for the point in time the data on this line is relevant. Note that the interval between timestamps increases as you
prograss through the file. At first it is 5 minutes and at the end it is one day between two lines.
This timestamp may be converted in OpenOffice Calc or MS Excel by using the following formula
=(x+y)/86400+DATE(1970;1;1)
(instead of ";" it may be that you have to use "," this depends on the context and your locale settings)
you can also ask perl to help by typing
perl -e 'print scalar localtime(x),"
"'
x is the unix timestamp and y is the offset in seconds from UTC. (Perl knows y).
B (2nd column)
The average incoming transfer rate in bytes per second. This is valid for the time between the A value of the current line and the A
value of the previous line.
C (3rd column)
The average outgoing transfer rate in bytes per second since the previous measurement.
D (4th column)
The maximum incoming transfer rate in bytes per second for the current interval. This is calculated from all the updates which have
occured in the current interval. If the current interval is 1 hour, and updates have occured every 5 minutes, it will be the biggest 5
minute transfer rate seen during the hour.
E (5th column)
The maximum outgoing transfer rate in bytes per second for the current interval.
AUTHOR
Butch Kemper <kemper@bihs.net> and Tobias Oetiker <tobi@oetiker.ch>
2.16.2 2008-05-16 MRTG-LOGFILE(1)