I am trying to validate user input, at the moment what i have is as below :-
echo "\n\tPlease, enter package name to import: \c"
read PACKAGE
So far this works perfect , But if the user does not input any thing it stalls :(
What I need is, If the user does not enter the name of the... (9 Replies)
The script below performs an incremental database backup. When the increment backup is out of sequence, the process prompts the user:
"Incremental backup out of sequece. Do you wish to continue? Y or N". This script is set to run as a scheduled process in background mode. When the script... (2 Replies)
Hi guys, I have a piece of snippet below which asks the user to input some numbers
if isDatasubEnabled && isReconEnabled; then
echo "1 = CGT, 2 = Subscriber, 3 = Order Monitor, 4 = Revaluations, 5 = Reconciliation, 6 = All, 7 = Exit"
elif isDatasubEnabled &&... (4 Replies)
Hello Everyone,
I have the following script;
------------------------------------------------------------------
#!/bin/ksh
set HSC=$1
set SEX=$2
set EXP='export ORACLE_SID=AFISDB'
if ($#argv !=2);
then
echo Usage $0 HSC SEX
else
date > modify_gender_trace.txt
$EXP
echo... (5 Replies)
Hello all,
I am working on a script and have the first part solved of numerical input validation. Below the code validates that the input is a numerical value between 100 and 1000. If not, it errors out. Now I need to be able to read values separated by a comma. For example, instead of my... (5 Replies)
Hi,
I'm trying to do input validation for a file. If the user fails to enter a file name, the script should prompt for the file name or exit. I'm using this script to integrate with a bigger script which does ftp of the files which are "read".
#!/bin/ksh
echo "enter a file name"
if
then... (16 Replies)
The Code:
#!/usr/bin/perl
use strict;
use warnings;
print "Please enter numbers, separated by commas: ";
my $data=<STDIN>; chomp $data;
my @dataset=split(/,/, $data);
my $sum = 0;
foreach my $num (@dataset) {
$sum += $num;
}
my $total_nums = scalar(@dataset);
my $mean =... (1 Reply)
i have a script which takes input from user, if user gives either Y/y then it should continue, else it should quit by displaying user cancelled.
#!/bin/sh
echo " Enter your choice to continue y/Y OR n/N to quit "
read A
if
then
echo " user requested to continue "
##some commands... (7 Replies)
Hi
I need to put the validation in batch script when user will enter the build number it should be numeric.I can put the validation for numeric values but there is .(dot) in number so it would not take it as numeric.
Is it possible we can store it in variable and remove the .(dot) from the... (1 Reply)
Hi Experts,
I've a script where users will input the email id. I want to loop the script until the user enter proper email id.
Its validating for all condition and error out if any wrong data, but for one condition alone its not erroring out.
Capture_EmailID()
{
echo -e "Please Enter... (1 Reply)
Discussion started by: senthil.ak
1 Replies
LEARN ABOUT PHP
fbsql_field_type
FBSQL_FIELD_TYPE(3) 1 FBSQL_FIELD_TYPE(3)fbsql_field_type - Get the type of the specified field in a resultSYNOPSIS
string fbsql_field_type (resource $result, [int $field_offset])
DESCRIPTION fbsql_field_type(3) is similar to the fbsql_field_name(3) function, but the field type is returned instead.
PARAMETERS
o $
result -A result identifier returned by fbsql_query(3) or fbsql_db_query(3).
o $field_offset
- The numerical offset of the field. The field index starts at 0.
RETURN VALUES
Returns the field type, as a string.
This can be one of int, real, string, blob, and others as detailed in the FrontBase documentation.
EXAMPLES
Example #1
fbsql_field_type(3) example
<?php
fbsql_connect("localhost", "_SYSTEM", "");
fbsql_select_db("wisconsin");
$result = fbsql_query("SELECT * FROM onek;");
$fields = fbsql_num_fields($result);
$rows = fbsql_num_rows($result);
$i = 0;
$table = fbsql_field_table($result, $i);
echo "Your '" . $table . "' table has " . $fields . " fields and " . $rows . " records <br />";
echo "The table has the following fields <br />";
while ($i < $fields) {
$type = fbsql_field_type($result, $i);
$name = fbsql_field_name($result, $i);
$len = fbsql_field_len($result, $i);
$flags = fbsql_field_flags($result, $i);
echo $type . " " . $name . " " . $len . " " . $flags . "<br />";
$i++;
}
fbsql_close();
?>
SEE ALSO fbsql_field_name(3).
PHP Documentation Group FBSQL_FIELD_TYPE(3)