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Full Discussion: UNIX script -- case
Top Forums Shell Programming and Scripting UNIX script -- case Post 302764875 by SSUUser on Friday 1st of February 2013 05:35:35 AM
Old 02-01-2013
Quote:
Originally Posted by zazzybob
Why must you use the case construct? This smells like homework. If this were a "real world" requirement, case is not required here, an if/else would do the job.

In any case, your syntax is totally invalid.
..that is not homework . I know how to do it in using if command . I know there are a lot of kids looking for stuff and they dont wanna pay for it .

Code:
#!/bin/sh
if [ $1 -ge 1 ]
then
echo "it is greater than or equal to 1"
else
echo " it is little than 1"
fi

---------- Post updated at 05:35 AM ---------- Previous update was at 05:34 AM ----------

i said I must use case command because i wanna try sth new and whether it is possible .
Program needs new creation* , right ?

Last edited by Scrutinizer; 02-01-2013 at 06:48 AM.. Reason: code tags
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
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