Explanation of print statement - awk Post: 302764773

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Top Forums Shell Programming and Scripting Explanation of print statement - awk Post 302764773 by Don Cragun on Friday 1st of February 2013 01:25:50 AM

02-01-2013

Registered User

Quote:

Originally Posted by Corona688

I can see why you're puzzled, that took some thought.

Nothing at all is assigned to X. It's printing a newline. print "" would have the same effect, but they saved one character by using a blank variable. Just print all by itself with no parameters would print the entire line, not what you want.

The printf statements do not print newlines, those must be explicit when using printf. So it prints a bunch of things into one long line, then uses print "" to finish off the line.

Are you sure that's OFS,$i and not OFS $i ? Two things into a single %s is a syntax error as far as I know.

It isn't a syntax error, but it isn't common. The awk printf command:

Code:

printf "%s" OFS,$i

uses the concatenation of "%s" and OFS as a format string; together they print the contents of the ith input field followed by the output field separator. If there is a bug here, it is that there is an extraneous trailing field separator printed at the end of each output line before the <newline> added by the print x command.

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