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Top Forums Shell Programming and Scripting Explanation of print statement - awk Post 302764745 by theflamingmoe on Thursday 31st of January 2013 10:19:01 PM
Old 01-31-2013
Explanation of print statement - awk

Hi, i'm just after a simple explanation of how the following awk oneliner works.
Code:
 
gawk -F"," '{for(i=m;i<=n;i++)printf "%s" OFS,$i; print x}' m=1 n=70 OFS=, input.csv > output.csv

In particular i'm trying to understand how the two print statements work? How is the "x" variable being assigned a value? Is the "x" variable being assigned the value of the first printf statement?

Thanks in advance,
TheFlamingMoe
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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