Sponsored Content
Top Forums Shell Programming and Scripting Command substitution inside of a variable expression (AIX, KORN) Post 302761159 by Subbeh on Friday 25th of January 2013 08:39:43 AM
Old 01-25-2013
Your code works fine for me under Solaris.

Maybe try cd ${1:-$PWD} instead.
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

sed insert command and variable expansion/command substitution

I know this script is crummy, but I was just messing around.. how do I get sed's insert command to allow variable expansion to show the filename? #!/bin/bash filename=`echo $0` /usr/bin/sed '/#include/ { i\ the filename is `$filename` }' $1 exit 0 (8 Replies)
Discussion started by: glev2005
8 Replies

2. Shell Programming and Scripting

Making script show command (e.g. copy) being executed and variable substitution?

When script is running you only see when some of the commands are not successfull. Is there a way to see which command are executed and to show the substitution of variables as every line is executed ? (3 Replies)
Discussion started by: gr0124
3 Replies

3. Shell Programming and Scripting

How to use variable with command substitution in variable

For example I have variable like below echo $OUTPUT /some/path/`uname -n` when I try to use the variable OUTPUT like below cd $OUTPUT or cd ${OUTPUT} I am getting bad substituion error message $ cd $OUTPUT ksh: cd: bad substitution $ cd ${OUTPUT} ksh: cd: bad substitution ... (1 Reply)
Discussion started by: rajukv
1 Replies

4. Shell Programming and Scripting

How to use same variable value inside as well as outside of the awk command?

Hi Jim, The following script is in working state. But i m having one more problem with awk cmd. Could you tell me how to use any variable inside awk or how to take any variable value outside awk. My problem is i want to maintain one property file in which i am declaring variable value into that... (12 Replies)
Discussion started by: Ganesh Khandare
12 Replies

5. Shell Programming and Scripting

Not able to store command inside a shell variable, and run the variable

Hi, I am trying to do the following thing var='date' $var Above command substitutes date for and in turn runs the date command and i am getting the todays date value. I am trying to do the same thing as following, but facing some problems, unique_host_pro="sed -e ' /#/d'... (3 Replies)
Discussion started by: gvinayagam
3 Replies

6. Shell Programming and Scripting

[Solved] Command Substitution and Variable Expansion within a Case

Hello All, I don't write scripts very often, and in this case I am stumped, although it may be a bug in the version of bash I have to use (it's not my system). I want to extract a specific string snippet from a block of text (coming from a log file) that is dependent on a bunch of other... (1 Reply)
Discussion started by: jaimielives
1 Replies

7. UNIX for Dummies Questions & Answers

Variable inside command substitution

Hello people. Part of my script: SUBSETID=`echo $PMFILE |sed 's/pmresult_//' | sed 's/_*//'` MAPFILE=`find /huawei/cell /huawei/nodeb /huawei/rnc -name 'mapping_$SUBSETID.txt' |grep -v backup` Unfortunatelly variable $SUBSETID in the MAPFILE declaration will not return the... (3 Replies)
Discussion started by: drbiloukos
3 Replies

8. UNIX for Dummies Questions & Answers

[solved]Korn, disabling * substitution

If I execute the following line of code: echo "*" I get a list of files in the current directory. What if all I wanted to do was display the asterisk itself? What does the code have to look like so all I get is an asterisk? Thanks ahead of time for your assistance ----------... (3 Replies)
Discussion started by: Wreckoning
3 Replies

9. Shell Programming and Scripting

Store command inside variable

Is it possible to store a command inside a variable? i want this piece to be stored inside a variable, so i can use it later in a different command $u | cut -d " " -f 2 var="$u | cut -d " " -f 2" eval $var I tried to use eval but I receive this error: -f 2: command not found ... (5 Replies)
Discussion started by: velos
5 Replies

10. Shell Programming and Scripting

String variable as part of expression in find command

Hi, I am new in scripting, and I am currently working on a script that will look for other files in a certain directory and exclude some file type. this works fine:Find_File2Exclude=`find ${paths} -maxdepth 1 -type f \( ! -iname '*.out' ! -iname '*.auc' ! -iname '*.cps' ! -iname '*.log' ! -iname... (4 Replies)
Discussion started by: kedd05
4 Replies
PWD(1)							    BSD General Commands Manual 						    PWD(1)

NAME
pwd -- return working directory name SYNOPSIS
pwd [-LP] DESCRIPTION
pwd writes the absolute pathname of the current working directory to the standard output. The following options are available: -L If the PWD environment variable is an absolute pathname that contains neither "/./" nor "/../" and references the current directory, then PWD is assumed to be the name of the current directory. -P Print the physical path to the current working directory, with symbolic links in the path resolved. The default for the pwd command is -P. pwd is usually provided as a shell builtin (which may have a different default). EXIT STATUS
The pwd utility exits 0 on success, and >0 if an error occurs. SEE ALSO
cd(1), csh(1), ksh(1), sh(1), getcwd(3) STANDARDS
The pwd utility is expected to be conforming to IEEE Std 1003.1 (``POSIX.1''), except that the default is -P not -L. BUGS
In csh(1) the command dirs is always faster (although it can give a different answer in the rare case that the current directory or a con- taining directory was moved after the shell descended into it). pwd -L relies on the file system having unique inode numbers. If this is not true (e.g., on FAT file systems) then pwd -L may fail to detect that PWD is incorrect. BSD
October 30, 2003 BSD
All times are GMT -4. The time now is 05:45 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy