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Top Forums Shell Programming and Scripting Shell script to copy particular file from directories recursively Post 302760215 by Optimus81 on Wednesday 23rd of January 2013 03:32:21 PM
Old 01-23-2013
Thanks Chubler. your solution did work as expected but am trying change the ouput file name as *_result.txt. I tried to update this line like this but didn't work
Code:
log=$(basename "$dest"_result .cnf).txt

Could you please tell me what am doing is correct in above stmt and if possible can you tell me how to acrchive this generated file (input/output) to someother path. so that if we run this script again it should genreated the new set of input/output file then it should generate new compare result file by comparing pervious result and new result file.

like :
1. generate input/result file (already done by above script)

2. If we run the above script again, it should check if there is any files present in output folder if yes, then move this genereated files to someother location with datetime stamp in the filename(archive) . if no files found then just generate files.

3. from step 2, if new set of results files generated (if files archived), then should compare archived result file to newly genereated result file.
ie, something like this
Code:
sdiff -s old_result_file new_result_file

please do help me on this.

ManyThanks,
 

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DB2_NUM_FIELDS(3)							 1							 DB2_NUM_FIELDS(3)

db2_num_fields - Returns the number of fields contained in a result set

SYNOPSIS
int db2_num_fields (resource $stmt) DESCRIPTION
Returns the number of fields contained in a result set. This is most useful for handling the result sets returned by dynamically generated queries, or for result sets returned by stored procedures, where your application cannot otherwise know how to retrieve and use the results. PARAMETERS
o $stmt - A valid statement resource containing a result set. RETURN VALUES
Returns an integer value representing the number of fields in the result set associated with the specified statement resource. Returns FALSE if the statement resource is not a valid input value. EXAMPLES
Example #1 Retrieving the number of fields in a result set The following example demonstrates how to retrieve the number of fields returned in a result set. <?php $sql = "SELECT id, name, breed, weight FROM animals ORDER BY breed"; $stmt = db2_prepare($conn, $sql); db2_execute($stmt, $sql); $columns = db2_num_fields($stmt); echo "There are {$columns} columns in the result set."; ?> The above example will output: There are 4 columns in the result set. SEE ALSO
db2_execute(3), db2_field_display_size(3), db2_field_name(3), db2_field_num(3), db2_field_precision(3), db2_field_scale(3), db2_field_type(3), db2_field_width(3). PHP Documentation Group DB2_NUM_FIELDS(3)
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