hii all.
I have to get the date of the 7th day past from the current date.
if i give the current date as sep 3 then i must get the date as 27th of august.
can we get the values from the "cal" command.
cal | awk '{print $2}' will this type of command work.
actually my need is
if today is... (17 Replies)
Hi,
Anybody knows how to get what date was 28 days ago of the current system date through UNIX script.
Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
Hi i am writing a cron job.
so for it i need the 60 days old date form current date in variable.
Like today date is 27 jan 2011 then output value will be stote in variable in formet Nov 27.
i am using EST date, and tried lot of solution and see lot of post but it did not helpful for me. so... (3 Replies)
I am trying to find out the number of days between the current date and user defined date.
I took reference from here for the date2jd() function.
Modified the function according to my requirement. But its not working properly.
Original code from here is working fine.
#!/bin/sh... (1 Reply)
Hi! I am trying to read a file and every line has a specific date as one of its fields.
I want to take that date and compare it to the date today plus 6 days.
while read line
do
date=substr($line, $datepos, 8) #date is expected to be YYYYMMDD
if ; then
...proceed commands
... (1 Reply)
Hi,
One of my Unix scripts needs to look for files coming in on Fridays. This script runs on Mondays. $date +"%y%m%d" will give me today's date. How can I get previous Friday's date.. can I do "today's date minus 3 days" to get Friday's date? If not, then any other way?? Name of the files is... (4 Replies)
I have to display only those subscribers which are in "unconnected state" and the date is 90 days older than today's date.
Below command is used for this purpose:
cat vfsubscriber_20170817.csv | sed -e 's/^"//' -e '1d' | nawk -F '",' '{if ( (substr($11,2,4) == 2017) && ( substr($11,2,8) -lt... (1 Reply)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT DEBIAN
lchage
lchage(8) System Manager's Manual lchage(8)NAME
lchage - Display or change user password policy
SYNOPSIS
lchage [OPTION]... user
DESCRIPTION
Displays or allows changing password policy of user.
OPTIONS -d, --date=days
Set the date of last password change to days after Jan 1 1970.
-E, --expire=days
Set the account expiration date to days after Jan 1 1970. Set days to -1 to disable account expiration.
-i, --interactive
Ask all questions when connecting to the user database, even if default answers are set up in libuser configuration.
-I, --inactive=days
Disable the account after days after password expires (after the user user is required to change the password).
-l, --list
Only list current user's policy and make no changes.
-m, --mindays=days
Require at least days days between password changes. Set days to 0 to disable this checking.
-M, --maxdays=days
Require changing the password after days since last password change. Set days to 99999 to disable this checking.
-W, --warndays=days
Start warning the user days before password expires (before the user is required to change the password).
EXIT STATUS
The exit status is 0 on success, nonzero on error.
libuser Jan 12 2005 lchage(8)