Hi Scrutinizer ,
Thanks, but the sed did not work well,
please advise, how not to print, first and last line if pattern matches to the first and last line.
It did not removed the last "vg" pattern matched entry. /dev/vgQ4XT
I need to replace the line containing "STAGE_DB" with the line
"STAGE_DB $DB # database that contains the table being loaded ($workingDB)"
Here $DB is passed during the runtime.
How can I do this?
Thanks,
Kousikan (2 Replies)
Hi How Are you?
I am doing fine!
I need to go now?
I will see you tomorrow!
Basically I need to replace the entire line containing "doing" with a blank line:
I need to the following output:
Hi How Are you?
I need to go now?
I will see you tomorrow!
Thanks in advance.... (1 Reply)
Data:
Pattern Data Data Data
Data Data Data
Data Data Data
...
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OS:: UNIX
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Version: xxx
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