I want to change a date from format dd-mmm-yyyy to mm/dd/yyyy. Is there a way to do this with sed or do you have to write a case statement to convert JAN to 01? Thanks (9 Replies)
How to convert the date field from dd/mm/yyyy to yyyy/mm/dd in unix
my script will generate text file which have two fields
one is date and another is name of the server for example this is sample date which I have to sort based on older to newer date the problem is when I found out sort will... (4 Replies)
I have a file which has 100k+ records like this
abc,05-JUN-1974,def,lkj,aaa
def,11-SEP-1975,ghj,dis,dea
I want to convert ex 05-JUN-1974 to 06/05/1974
Please help me with awk script to convert the whole file into MM-DD-YYYY
Thank you! (2 Replies)
Hi all
I have some pipe-separated data in the form:
5/12/2008 00:00:00|31/1/2009 00:00:00|SOMESTUFF|OTHERSTUFF
12/31/2008 00:00:00|15/1/2009 00:00:00|MORESTUFF|REMAININGSTUFF
1/1/1023 00:00:00|16/5/2047 00:00:00|THEREST|YETMORE
I need to zero-pad the single-digit days and months, using... (3 Replies)
My csv has data like this
x,x,3452,2/18/1986,abc
x,g,19711,1/24/1986,abc
i want to replace date in the following format YYYY-mm-dd
how do i convert using awk script ? (8 Replies)
(Attention: Green PHP newbie !)
I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
Hello,
I am writing a script that parses different logs and produces one. In the source files, the date is in DD MM YYYY HH24:MI:SS format. In the output, it should be in DD MON YYY HH24:MI:SS (ie 25 Jan 2010 16:10:10)
To extract the dates, I am using shell substrings, i.e.:
read line
... (4 Replies)
Hi I have a problem with Date format in my code.
1st I am trying to convert today's date to yesterday's using
YESTERDAY3=`perl -e '@y=localtime(time()-86400); printf "%04d/%02d/%02d",$y+1900,$y+1,$y;$y;'`
And once it is done I am trying to using the yesterday date in a grep command to... (3 Replies)
Hi Experts,
I'm facing an issue with date. My requirement is as follows
./script "dd/mm/yy" or ./script "dd/mm/yyyy"
epoch time
Im using solaris 10 and have downloaded gnu date.
I have tried using
$/usr/local/bin/date -d '25/02/2013'
/usr/local/bin/date: invalid date... (19 Replies)
I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY.
When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD
file... (3 Replies)
Discussion started by: Roozo
3 Replies
LEARN ABOUT CENTOS
cpan::changes::release
CPAN::Changes::Release(3) User Contributed Perl Documentation CPAN::Changes::Release(3)NAME
CPAN::Changes::Release - Information about a particular release
SYNOPSIS
my $rel = CPAN::Changes::Release->new(
version => '0.01',
date => '2009-07-06',
);
$rel->add_changes(
{ group => 'THINGS THAT MAY BREAK YOUR CODE' },
'Return a Foo object instead of a Bar object in foobar()'
);
DESCRIPTION
A changelog is made up of one or more releases. This object provides access to all of the key data that embodies a release including the
version number, date of release, and all of the changelog information lines. Any number of changelog lines can be grouped together under a
heading.
METHODS
new( %args )
Creates a new release object, using %args as the default data.
version( [ $version ] )
Gets/sets the version number for this release.
date( [ $date ] )
Gets/sets the date for this release.
changes( [ $group ] )
Gets the list of changes for this release as a hashref of group/changes pairs. If a group name is specified, an array ref of changes for
that group is returned. Should that group not exist, undef is returned.
add_changes( [ \%options ], @changes )
Appends a list of changes to the release. Specifying a "group" option appends them to that particular group. NB: the default group is
represented by and empty string.
# Append to default group
$release->add_changes( 'Added foo() function' );
# Append to a particular group
$release->add_changes( { group => 'Fixes' }, 'Fixed foo() function' );
set_changes( [ \%options ], @changes )
Replaces the existing list of changes with the supplied values. Specifying a "group" option will only replace change items in that group.
clear_changes( )
Clears all changes from the release.
groups( sort => &sorting_function )
Returns a list of current groups in this release.
If sort is provided, groups are sorted according to the given function. If not, they are sorted alphabetically.
add_group( @groups )
Creates an empty group under the names provided.
delete_group( @groups )
Deletes the groups of changes specified.
delete_empty_groups( )
Deletes all groups that don't contain any changes.
serialize( group_sort => &sorting_function )
Returns the release data as a string, suitable for inclusion in a Changes file.
If group_sort is provided, change groups are sorted according to the given function. If not, groups are sorted alphabetically.
SEE ALSO
o CPAN::Changes::Spec
o CPAN::Changes
o Test::CPAN::Changes
AUTHOR
Brian Cassidy <bricas@cpan.org>
COPYRIGHT AND LICENSE
Copyright 2011-2013 by Brian Cassidy
This library is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
perl v5.16.3 2013-05-02 CPAN::Changes::Release(3)