This means running find 74 times. Why not ls them all and then grep with the names file:
You could add a wc (word count) to check the 74, or you could compare the output to your names file to identify single missing files.
Actually, this will take ls's output as the pattern file and print the missing files for you:
Last edited by RudiC; 01-11-2013 at 05:00 AM..
Reason: quick solution added
I need help in forming a script to copy files from one location which has a sub directory structure to another location with similar sub directory structure,
say location 1,
/home/rick/tmp_files/1-12/00-25/
here 1-12 are the number of sub directories under tmp_files and 00-25 are sub... (1 Reply)
Create a script that copies files from one specified directory to another specified directory, in the order they were created in the original directory between specified times. Copy the files at a specified interval. (2 Replies)
Hi,
I am new to unix and shell scripting.
Please help me in resolving the below issue.
In my shell script I have a variable which stores the different files with the path. Now I need to move all the files one by one to another location.
----
1.... (4 Replies)
All,
I am trying to find a set of files, it could be one file OR set of file ,
all with extension .DAT
I need to do some acticity, only if the files exist in a partificular folder
like
if ; then
CntV=`ls $Landing/*.DAT |wc -l`
echo "Lst Value " $Cnt... (3 Replies)
Hi
This is my third past and very impressed with previous post replies
Hoping the same for below query
How to find a existing file location and directory location in solaris box (1 Reply)
Hello All,
Can someone please help me out in creating the find command to search and delete files older than 1 days at a desired location.
Thanks in advance for your help. (3 Replies)
A) I would like to achive following actions using shell script. can someone help me with writing the shell script
1) Go to some dir ( say /xyz/logs ) and then perform find operation in this dir and list of subdir using
find . -name "*" -print | xargs grep -li 1367A49001CP0162 >... (1 Reply)
Hello all,
I want to find the files for certain users. I cant make the or condition work in this instance. I've tried the code below but it didnt worked. Any input on how to get the list for all files for this users.
find . -type f -user abc134 -o -user xyz345 -o bce483 -exec ls... (6 Replies)
Hello there wonderful people,
I am running on Solaris 10 and with the following ksh version:
strings /bin/ksh | grep Version | tail -2
@(#)Version M-11/16/88i
Suppose I want to copy files that end in _v2 from underneath /dir1/dir2/save directory to /dir1/dir2. Basically, what I’m... (12 Replies)
Discussion started by: ejianu
12 Replies
LEARN ABOUT NETBSD
zgrep
ZGREP(1) BSD General Commands Manual ZGREP(1)NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files
SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...]
zegrep [grep-flags] [--] pattern [file ...]
zfgrep [grep-flags] [--] pattern [file ...]
DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1).
The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern
argument.
zegrep calls egrep(1), while zfgrep calls fgrep(1).
EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0.
SEE ALSO egrep(1), fgrep(1), grep(1), gzip(1), zcat(1)AUTHORS
Thomas Klausner <wiz@NetBSD.org>
BSD December 28, 2003 BSD