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Top Forums UNIX for Dummies Questions & Answers Find a set of files in a location Post 302754743 by RudiC on Friday 11th of January 2013 03:54:42 AM
Old 01-11-2013
This means running find 74 times. Why not ls them all and then grep with the names file:
Code:
ls -l /your_directory_name | grep -f my_file_names.txt

You could add a wc (word count) to check the 74, or you could compare the output to your names file to identify single missing files.
Actually, this will take ls's output as the pattern file and print the missing files for you:
Code:
ls|grep -vf - names


Last edited by RudiC; 01-11-2013 at 05:00 AM.. Reason: quick solution added
 

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ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...] zegrep [grep-flags] [--] pattern [file ...] zfgrep [grep-flags] [--] pattern [file ...] DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1). The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern argument. zegrep calls egrep(1), while zfgrep calls fgrep(1). EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0. SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1) AUTHORS
Thomas Klausner <wiz@NetBSD.org> BSD
December 28, 2003 BSD
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