Sponsored Content
Top Forums Shell Programming and Scripting Difficulty in understanding sort command Post 302754375 by bioinfo on Thursday 10th of January 2013 01:11:53 PM
Old 01-10-2013
Thanks Corona688. Smilie
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Need Help Understanding a Unix Command

Trying to install something. Can someone explain what this means? chmod -R a+r . chmod -R a+w logo.gif tempdir/ templates_c/ I recognize that file permissions are being changed (chmod), but beyond that, it's Greek to me. (6 Replies)
Discussion started by: chris86
6 Replies

2. Shell Programming and Scripting

understanding the sed command

Guys, I am trying to understand the sed command here. adx001 $ a=/clocal/dctrdata/user/dctrdat1/trdroot/recouncil adx001 $ b=`echo $a | sed 's/\//\\\\\//g'` adx001 $ echo $b \/clocal\/dctrdata\/user\/dctrdat1\/trdroot\/recouncil The sed command i took it from the script. Please... (3 Replies)
Discussion started by: mac4rfree
3 Replies

3. Shell Programming and Scripting

understanding the kill command

Hi Guys, I like to know if i have a process which triggers 10 different child processes. How to identify out of the 11 processes running which is the parent process and what are the child process? And if i kill the parent process will the child process be killed.. if not is there a way to... (2 Replies)
Discussion started by: mac4rfree
2 Replies

4. Shell Programming and Scripting

understanding mv command

hi i was moving a file from one directory to another with the following cmmand mv /home/hsghh/dfd/parent/file.txt . while doing so i i accidently mv /home/hsghh/dfd/dfd . although i gave ctrl c and terminate the move command some of the file are missing in the parent directory and... (1 Reply)
Discussion started by: saravanan71184
1 Replies

5. UNIX for Dummies Questions & Answers

Understanding the output command

Could you please explain me whats happening in the below code, appreciate your help, Thank you. /product/apps/informatica/v7/pc/ExtProc/NewDAC/dacRecBuilder.sh /product/apps/informatica/v7/pc/TgtFiles/NEW_DAC/DAC_Pos_TradeInv_Records.out ... (5 Replies)
Discussion started by: Ariean
5 Replies

6. Shell Programming and Scripting

How to Sort Floating Numbers Using the Sort Command?

Hi to all. I'm trying to sort this with the Unix command sort. user1:12345678:3.5:2.5:8:1:2:3 user2:12345679:4.5:3.5:8:1:3:2 user3:12345687:5.5:2.5:6:1:3:2 user4:12345670:5.5:2.5:5:3:2:1 user5:12345671:2.5:5.5:7:2:3:1 I need to get this: user3:12345687:5.5:2.5:6:1:3:2... (7 Replies)
Discussion started by: daniel.gbaena
7 Replies

7. Solaris

Understanding 'du' command

Hi I have a questions related 2 commands : 'du' and 'ls'. Why is the difference between output of 'du' and 'ls' cmd's ? Command 'du' : ------------------ jakubn@server1 /home/jakubn $ du -s * 4 engine.ksh 1331 scripts 'du -s *' ---> shows block count size on disk (512 Bytes... (5 Replies)
Discussion started by: presul
5 Replies

8. Shell Programming and Scripting

perl command understanding

Hi All, Can you please help me interpret the following command. Which I am not able to understand. Also can you please illustrate what it is used for. perl -pi -e 's/\015//g' text_file.dat Regards (3 Replies)
Discussion started by: rakesh.su30
3 Replies

9. UNIX for Dummies Questions & Answers

Difficulty with set - command

Hi , i have a shell script with the first two lines as #! /bin/ksh set -x when i try opening the file from unix using the command 'sh filename.sh' , i am getting the below error : invalid optionline 2: set: - Pls help Use code tags for you code and data... (1 Reply)
Discussion started by: Rajankum
1 Replies

10. Shell Programming and Scripting

awk : Need Help in Understanding a command

Hello I am working on a Change request and Stuck at a point. The below awk command is used in the function. float_test ( ) { echo | awk 'END { exit ( !( '"$1"')); }' } I understand that awk 'END' is used to add one line at the end and exit is used to end the script with an error... (4 Replies)
Discussion started by: rahul2662
4 Replies
sort(3pm)						 Perl Programmers Reference Guide						 sort(3pm)

NAME
sort - perl pragma to control sort() behaviour SYNOPSIS
use sort 'stable'; # guarantee stability use sort '_quicksort'; # use a quicksort algorithm use sort '_mergesort'; # use a mergesort algorithm use sort 'defaults'; # revert to default behavior no sort 'stable'; # stability not important use sort '_qsort'; # alias for quicksort my $current; BEGIN { $current = sort::current(); # identify prevailing algorithm } DESCRIPTION
With the "sort" pragma you can control the behaviour of the builtin "sort()" function. In Perl versions 5.6 and earlier the quicksort algorithm was used to implement "sort()", but in Perl 5.8 a mergesort algorithm was also made available, mainly to guarantee worst case O(N log N) behaviour: the worst case of quicksort is O(N**2). In Perl 5.8 and later, quicksort defends against quadratic behaviour by shuffling large arrays before sorting. A stable sort means that for records that compare equal, the original input ordering is preserved. Mergesort is stable, quicksort is not. Stability will matter only if elements that compare equal can be distinguished in some other way. That means that simple numerical and lexical sorts do not profit from stability, since equal elements are indistinguishable. However, with a comparison such as { substr($a, 0, 3) cmp substr($b, 0, 3) } stability might matter because elements that compare equal on the first 3 characters may be distinguished based on subsequent characters. In Perl 5.8 and later, quicksort can be stabilized, but doing so will add overhead, so it should only be done if it matters. The best algorithm depends on many things. On average, mergesort does fewer comparisons than quicksort, so it may be better when complicated comparison routines are used. Mergesort also takes advantage of pre-existing order, so it would be favored for using "sort()" to merge several sorted arrays. On the other hand, quicksort is often faster for small arrays, and on arrays of a few distinct values, repeated many times. You can force the choice of algorithm with this pragma, but this feels heavy-handed, so the subpragmas beginning with a "_" may not persist beyond Perl 5.8. The default algorithm is mergesort, which will be stable even if you do not explicitly demand it. But the stability of the default sort is a side-effect that could change in later versions. If stability is important, be sure to say so with a use sort 'stable'; The "no sort" pragma doesn't forbid what follows, it just leaves the choice open. Thus, after no sort qw(_mergesort stable); a mergesort, which happens to be stable, will be employed anyway. Note that no sort "_quicksort"; no sort "_mergesort"; have exactly the same effect, leaving the choice of sort algorithm open. CAVEATS
As of Perl 5.10, this pragma is lexically scoped and takes effect at compile time. In earlier versions its effect was global and took effect at run-time; the documentation suggested using "eval()" to change the behaviour: { eval 'use sort qw(defaults _quicksort)'; # force quicksort eval 'no sort "stable"'; # stability not wanted print sort::current . " "; @a = sort @b; eval 'use sort "defaults"'; # clean up, for others } { eval 'use sort qw(defaults stable)'; # force stability print sort::current . " "; @c = sort @d; eval 'use sort "defaults"'; # clean up, for others } Such code no longer has the desired effect, for two reasons. Firstly, the use of "eval()" means that the sorting algorithm is not changed until runtime, by which time it's too late to have any effect. Secondly, "sort::current" is also called at run-time, when in fact the compile-time value of "sort::current" is the one that matters. So now this code would be written: { use sort qw(defaults _quicksort); # force quicksort no sort "stable"; # stability not wanted my $current; BEGIN { $current = sort::current; } print "$current "; @a = sort @b; # Pragmas go out of scope at the end of the block } { use sort qw(defaults stable); # force stability my $current; BEGIN { $current = sort::current; } print "$current "; @c = sort @d; } perl v5.18.2 2013-11-04 sort(3pm)
All times are GMT -4. The time now is 08:49 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy