Sponsored Content
Top Forums Shell Programming and Scripting Cannot pass rsh and awk command into a variable Post 302753891 by Corona688 on Wednesday 9th of January 2013 02:03:36 PM
Old 01-09-2013
There's no point listing the permissions, user and group ownership, file size, and modification time when you're going to just strip that all back out with awk. Simplifying that statement may help it work, so try this:

Code:
VAR=`rsh server "(ls -d /home*/user)"`

This User Gave Thanks to Corona688 For This Post:
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

pass variable to awk

i would like to pass a variable to awk wherein the variable comes from external loop. i tried this... let x=0 until test $x -eq 32 do cat file | awk '{ print $1 , "Number" , $($x) }' >> output done thanks, (4 Replies)
Discussion started by: inquirer
4 Replies

2. Shell Programming and Scripting

can I pass awk variable to system command?

I wanna use a system function to deal with several data. So I use awk variable FILENAME to transfer the file directory to system command, but it does not work. I use a shell function "out_function" to deal with data and save the result in another directory with the same file name. How can I... (2 Replies)
Discussion started by: zhynxn
2 Replies

3. Shell Programming and Scripting

How to pass a variable to Awk ?

I am trying to pass 2 shell variable's ("START" and "END") define earlier in the script to this awk statement, but i can't seem to pass it on. PLs help. set START = xxxx set END = yyyy set selected_file = `awk '/$START/,/$END/' filename` (24 Replies)
Discussion started by: Raynon
24 Replies

4. UNIX for Dummies Questions & Answers

How do I pass a variable to awk?

I have an awk statement where I Need to pass an environment variable but I cannot get it to work: My evironment varible examples below: $FILE1=/dev/fs/file.new $FILE2=/dev/fs/file.old Code below: awk -F"|" ' BEGIN { while( getline < "$FILE1" ) { arr=1 } } arr != 1 { print } '... (12 Replies)
Discussion started by: eja
12 Replies

5. Shell Programming and Scripting

Pass script variable value to AWK

HI all, some more mistery about AWK, I hope you can help me out: 1) I have a normal ksh script and sometime I call awk command. I set some variables in the script and I would like to use them up within AWK as well. Unfortunately AWK seems to forget all the variable values outside of its own... (1 Reply)
Discussion started by: BearCheese
1 Replies

6. Shell Programming and Scripting

how to pass variable in NR function used in awk command?

Hi I want to pass variables with the NR function in awk command. test_file1 is input file having 500 records. var1=100. var2=200 awk -F" " 'NR >= $var1 && NR <= $var2' test_file1 > test_file2. My end result should be that test_file2 should have records from line number between... (2 Replies)
Discussion started by: Nishithinfy
2 Replies

7. Shell Programming and Scripting

awk, double variable, for loop and rsh

Hello folks, I've a (perhaps) simple question. In a text file I've : server_name1: directory1 server_name2: directory2 server_name3: directory3 I want to make a loop that lets me connect and operate on every server: rsh server_name1 "ls -l directory1" I've tried with awk,... (6 Replies)
Discussion started by: gogol_bordello
6 Replies

8. Shell Programming and Scripting

Unable to pass shell script variable to awk command in same shell script

I have a shell script (.sh) and I want to pass a parameter value to the awk command but I am getting exception, please assist. diff=$1$2.diff id=$2 new=new_$diff echo "My id is $1" echo "I want to sync for user account $id" ##awk command I am using is as below cat $diff | awk... (2 Replies)
Discussion started by: Ashunayak
2 Replies

9. UNIX for Advanced & Expert Users

Pass variable to awk command search string

I must have forgot how to do this, but, I am attempting to enter a variable into an awk / gawk search pattern. I am getting a value from user input to place in a specific section of a 132 character string. my default command is .... gawk --re-interval '/^(.{3}P .{4}CYA.{8}1)/' ... (3 Replies)
Discussion started by: sdeevers
3 Replies

10. UNIX for Beginners Questions & Answers

Need to pass variable in a command and assign value to a variable

Hello All, Hope you're doing well ! I am trying below command to be passed in a shell script, header_date_14 is a variable and $1 is the name of a file I intend to pass as a command line argument, however command line argument is not being accepted. header_date_14=$(m_dump... (8 Replies)
Discussion started by: ektubbe
8 Replies
LS(1)							      General Commands Manual							     LS(1)

NAME
ls - list contents of directory SYNOPSIS
ls [ -ltasdrucifg ] name ... DESCRIPTION
For each directory argument, ls lists the contents of the directory; for each file argument, ls repeats its name and any other information requested. The output is sorted alphabetically by default. When no argument is given, the current directory is listed. When several arguments are given, the arguments are first sorted appropriately, but file arguments appear before directories and their contents. There are several options: -l List in long format, giving mode, number of links, owner, size in bytes, and time of last modification for each file. (See below.) If the file is a special file the size field will instead contain the major and minor device numbers. -t Sort by time modified (latest first) instead of by name, as is normal. -a List all entries; usually `.' and `..' are suppressed. -s Give size in blocks, including indirect blocks, for each entry. -d If argument is a directory, list only its name, not its contents (mostly used with -l to get status on directory). -r Reverse the order of sort to get reverse alphabetic or oldest first as appropriate. -u Use time of last access instead of last modification for sorting (-t) or printing (-l). -c Use time of last modification to inode (mode, etc.) instead of last modification to file for sorting (-t) or printing (-l). -i Print i-number in first column of the report for each file listed. -f Force each argument to be interpreted as a directory and list the name found in each slot. This option turns off -l, -t, -s, and -r, and turns on -a; the order is the order in which entries appear in the directory. -g Give group ID instead of owner ID in long listing. The mode printed under the -l option contains 11 characters which are interpreted as follows: the first character is d if the entry is a directory; b if the entry is a block-type special file; c if the entry is a character-type special file; - if the entry is a plain file. The next 9 characters are interpreted as three sets of three bits each. The first set refers to owner permissions; the next to permissions to others in the same user-group; and the last to all others. Within each set the three characters indicate permission respectively to read, to write, or to execute the file as a program. For a directory, `execute' permission is interpreted to mean permission to search the directory for a specified file. The permissions are indicated as follows: r if the file is readable; w if the file is writable; x if the file is executable; - if the indicated permission is not granted. The group-execute permission character is given as s if the file has set-group-ID mode; likewise the user-execute permission character is given as s if the file has set-user-ID mode. The last character of the mode (normally `x' or `-') is t if the 1000 bit of the mode is on. See chmod(1) for the meaning of this mode. When the sizes of the files in a directory are listed, a total count of blocks, including indirect blocks is printed. FILES
/etc/passwd to get user ID's for `ls -l'. /etc/group to get group ID's for `ls -g'. LS(1)
All times are GMT -4. The time now is 08:48 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy