How to Replace the value of a column using awk command? Post: 302752433

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awk script to extract a column, replace one of the header and replace year(from ddmmyy to yyyy)

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LEARN ABOUT SUSE

html::formattext

HTML::FormatText(3)					User Contributed Perl Documentation				       HTML::FormatText(3)

NAME

       HTML::FormatText - Format HTML as plaintext

SYNOPSIS

	require HTML::TreeBuilder;
	$tree = HTML::TreeBuilder->new->parse_file("test.html");

	require HTML::FormatText;
	$formatter = HTML::FormatText->new(leftmargin => 0, rightmargin => 50);
	print $formatter->format($tree);

DESCRIPTION

       The HTML::FormatText is a formatter that outputs plain latin1 text.  All character attributes (bold/italic/underline) are ignored.
       Formatting of HTML tables and forms is not implemented.

       You might specify the following parameters when constructing the formatter:

       leftmargin (alias lm)
	   The column of the left margin. The default is 3.

       rightmargin (alias rm)
	   The column of the right margin. The default is 72.

SEE ALSO

       HTML::Formatter

COPYRIGHT

       Copyright (c) 1995-2002 Gisle Aas, and 2002- Sean M. Burke. All rights reserved.

       This library is free software; you can redistribute it and/or modify it under the same terms as Perl itself.

       This program is distributed in the hope that it will be useful, but without any warranty; without even the implied warranty of
       merchantability or fitness for a particular purpose.

AUTHOR

       Current maintainer: Sean M. Burke <sburke@cpan.org>

       Original author: Gisle Aas <gisle@aas.no>

perl v5.12.1							    2004-06-02						       HTML::FormatText(3)

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