Hi All,
I am new to bash scripting. I need your help to removing spaces from a string and assign them to different variables.
Iwant to call script with one command line argument which is file name which containes different attributes their type and different values eg
... (1 Reply)
I come across the problems when assigning the array in the script below . How to use the array with the 'string index' correctly ? When I assign a new string index , the array elements that are previously assigned are all changed .:eek::eek::eek:
$ array=211
$ echo ${array}
211
$... (4 Replies)
How...
can I read input by a user character by cahracter. And assign each character from the string to a variable?
Any help would be greatly appreciated!
Thank you! (1 Reply)
guys,
I need to know how to assing pattern matched string as an input command variable. Here it goes'
My script is something like this.
./routing.sh <Server> <enable|disable>
## This Script takes an input <Server> variable from this line of the script ##
echo $1 | egrep... (1 Reply)
I have a string as "yes why not"
I want to create one array variable with contents as one word per place in array..
for above string,the array variable should contain...
x="yes,why,not"
x = yes
x = why
x = not
Please help me,I am stuck up in the problem since 2 days... (3 Replies)
Hi ,I am trying to assign string to variable ,but it doesn't work
Also could you show me different ways to use grep,(I am trying to get the first,second and first column form file,and I am counting the chars)
let name=`grep "$id" product | cut -c6-20` (25 Replies)
Hello Experts,
In my script i am using the below syntax
/usr/bin/head -1 /opt/chumma.txt | /usr/bin/cut -d " " -f3
output of this one is --> Monday
I want to store this String in a variable (i.e) j or k...
Give me some idea experts.
Thanks in advance. (7 Replies)
I have several lines in a file that I want to replace a space with a tab.
For example:
111047 Julie Jones email@email.com
111047 Julie Jones email@email.com
I want to replace the space after the word "jones" with a tab.
How do I achieve that in Vi?
Please assist.
Thanks! (5 Replies)
I see a millioin ways to do this with echo, but what I wan to do is assign a variable the "nth" character of an incoming parameter to a ksh script.
$1 will be "pia"
I need to assign the first character to stmttype. (10 Replies)
Hi all, i'm new in shell script. i'm trying to do this:
mypid="ps | grep whileloop.sh | sed -n 1p | tr -s ' ' | cut -f2 -d' '"
i'm trying to assign the pid number to variable mypid, but it doesn't work...how can i do? thanks (5 Replies)
Discussion started by: Marina2013
5 Replies
LEARN ABOUT DEBIAN
viewperl
VIEWPERL(1) User Commands VIEWPERL(1)NAME
viewperl - quickly view syntax highlighted Perl code
SYNOPSIS
viewperl [OPTION]... FILE...
DESCRIPTION
View a Perl source code file, syntax highlighted.
-c, --code=CODE
view CODE, syntax highlighted
-l, --lines
display line numbers
-L, --no-lines
supress display of line numbers (default)
-m, --module=FILE
consider FILE the name of a module, not a file name
-n, --name
display the name of each file (default)
-N, --no-name
supress display of file names (implied by --no-reset)
-p, --pod
display inline POD documentation (default)
-P, --no-pod
hide POD documentation (line numbers still increment)
-r, --reset
reset formatting and line numbers each file (default)
-R, --no-reset
supress resetting of formatting and line numbers
-s, --shift=WIDTH
set tab width (default is 4)
-t, --tabs
translate tabs into spaces (default)
-T, --no-tabs
supress translating of tabs into spaces
--help display this help and exit
Note that module names should be given as they would appear after a Perl `use' or `require' statement. `Getopt::Long', for example.
Each string given using -c is considered a different file, so line number and formatting resets will apply.
View a Perl source code file, syntax highlighted.
-c, --code=CODE
view CODE, syntax highlighted
-l, --lines
display line numbers
-L, --no-lines
supress display of line numbers (default)
-m, --module=FILE
consider FILE the name of a module, not a file name
-n, --name
display the name of each file (default)
-N, --no-name
supress display of file names (implied by --no-reset)
-p, --pod
display inline POD documentation (default)
-P, --no-pod
hide POD documentation (line numbers still increment)
-r, --reset
reset formatting and line numbers each file (default)
-R, --no-reset
supress resetting of formatting and line numbers
-s, --shift=WIDTH
set tab width (default is 4)
-t, --tabs
translate tabs into spaces (default)
-T, --no-tabs
supress translating of tabs into spaces
--help display this help and exit
Note that module names should be given as they would appear after a Perl `use' or `require' statement. `Getopt::Long', for example.
Each string given using -c is considered a different file, so line number and formatting resets will apply.
viewperl August 2007 VIEWPERL(1)