Hi
One of my vendor based tool is giving date in
no. of days since 1900-01-01.
So, I want to display in CCYYMMDD format.
For ex:- Vendor based tool is giving as 38790 days since 1900-01-01
corresponding to12/sep/2006
Does anybody has the... (1 Reply)
Hi experts,
Can you please help me in calculating the future date using unix shell scripting..
for example
lets say todays date is 29-sep-2008
i wanna calculate the date after 365 days...
hence the date must be 29-sep-2009..
Quick response is appreciable.
thanks in... (2 Replies)
Hi all,
i need a script that can check if users did an operation within 3 days,if not delete all the logs of users who did not perform any activity after 3 days.therefore script should be able to use current date and verify last date user performed activity and see if it is greater or less than 3... (3 Replies)
Hello all. I'm writing a script that should work with some files being sure that them were created a concrete day (0, 1, 2 or 3 days before script execution). This task should be done under Solaris and Linux hosts with different versions (Solaris 8, 9 and 10, Suse 9 and 10) so I'm trying to make... (3 Replies)
hello guys,
I had been to many forums and many topics in this site as well for my question but did not get any solution.
My question is how i can get y'day date with time stamp
today is 20100729103819 and i am looking for output as 20100728103819.
in simple words as we do in oracle sysdate-1... (4 Replies)
hello!
I need a date calculation script that need to do that:
./date.sh 20090312
and the script need to give me which day is it for example monday friday or what else!
can anyone help me?? its really urgent :S thx the help! (7 Replies)
I have to run a shell , only if file_a.txt is updated correctly before 1hr.
that is,
file_a.txt
2011_09_21__14:10:20 --> any format..
And
the shell can be like,
if ; then
Run some shell
update file_a.txt with (date now)
fi
how to do this ? (6 Replies)
Hello eveyone, I am tasked to write an (n)awk script to calculate the days between dates. Now before anyone chastizes me on how many forums there are on date calculation, I have no seen one that takes into account the Julian calender as well. As most know, September of 1752 is when we (the US)... (2 Replies)
Hi All,
I need to calculate the date for monday to friday.
Say today is 10.oct.2014 then I need to calculate the date as 09.oct.2014.
If today is 13.oct.2014 then I need to calculate the date as 10.oct.2014.
If its 03.Nov.2014 then date calculated must be 31.oct.2014.
Please help in in... (2 Replies)
I want to automate change in 'from yyyy/mm/dd to yyyy/mm/dd' every month in a unix program.
For example in this month 'from yyyy/mm/dd to yyyy/mm/dd' is 'from 2014/10/01 to 2014/11/01' next month it should be 'from 2014/11/01 to 2014/12/01'
Can any one provide me the code for the above... (2 Replies)
Discussion started by: srinivas kasett
2 Replies
LEARN ABOUT PHP
dateinterval.format
DATEINTERVAL.FORMAT(3) 1 DATEINTERVAL.FORMAT(3)DateInterval::format - Formats the interval
SYNOPSIS
public string DateInterval::format (string $format)
DESCRIPTION
Formats the interval.
PARAMETERS
o $format
-
The following characters are recognized in the $format parameter string. Each format character must be prefixed by a percent sign (
%).
+------------------+--------------------------------------+---+
|$format character | | |
| | | |
| | Description | |
| | | |
| | Example values | |
| | | |
+------------------+--------------------------------------+---+
| | | |
| % | | |
| | | |
| | Literal % | |
| | | |
| | | |
| | % | |
| | | |
| | | |
| Y | | |
| | | |
| | Years, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03 | |
| | | |
| | | |
| y | | |
| | | |
| | Years, numeric | |
| | | |
| | | |
| | 1, 3 | |
| | | |
| | | |
| M | | |
| | | |
| | Months, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 12 | |
| | | |
| | | |
| m | | |
| | | |
| | Months, numeric | |
| | | |
| | | |
| | 1, 3, 12 | |
| | | |
| | | |
| D | | |
| | | |
| | Days, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 31 | |
| | | |
| | | |
| d | | |
| | | |
| | Days, numeric | |
| | | |
| | | |
| | 1, 3, 31 | |
| | | |
| | | |
| a | | |
| | | |
| | Total number of days as a result of | |
| | a DateTime::diff or (unknown) other- | |
| | wise | |
| | | |
| | | |
| | 4, 18, 8123 | |
| | | |
| | | |
| H | | |
| | | |
| | Hours, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 23 | |
| | | |
| | | |
| h | | |
| | | |
| | Hours, numeric | |
| | | |
| | | |
| | 1, 3, 23 | |
| | | |
| | | |
| I | | |
| | | |
| | Minutes, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 59 | |
| | | |
| | | |
| i | | |
| | | |
| | Minutes, numeric | |
| | | |
| | | |
| | 1, 3, 59 | |
| | | |
| | | |
| S | | |
| | | |
| | Seconds, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 57 | |
| | | |
| | | |
| s | | |
| | | |
| | Seconds, numeric | |
| | | |
| | | |
| | 1, 3, 57 | |
| | | |
| | | |
| R | | |
| | | |
| | Sign " -" when negative, " +" when | |
| | positive | |
| | | |
| | | |
| | -, + | |
| | | |
| | | |
| r | | |
| | | |
| | Sign " -" when negative, empty when | |
| | positive | |
| | | |
| | | |
| | -, | |
| | | |
+------------------+--------------------------------------+---+
RETURN VALUES
Returns the formatted interval.
NOTES
Note
The DateInterval::format method does not recalculate carry over points in time strings nor in date segments. This is expected
because it is not possible to overflow values like "32 days" which could be interpreted as anything from "1 month and 4 days" to "1
month and 1 day".
EXAMPLES
Example #1
DateInterval example
<?php
$interval = new DateInterval('P2Y4DT6H8M');
echo $interval->format('%d days');
?>
The above example will output:
4 days
Example #2
DateInterval and carry over points
<?php
$interval = new DateInterval('P32D');
echo $interval->format('%d days');
?>
The above example will output:
32 days
Example #3
DateInterval and DateTime::diff with the %a and %d modifiers
<?php
$january = new DateTime('2010-01-01');
$february = new DateTime('2010-02-01');
$interval = $february->diff($january);
// %a will output the total number of days.
echo $interval->format('%a total days')."
";
// While %d will only output the number of days not already covered by the
// month.
echo $interval->format('%m month, %d days');
?>
The above example will output:
31 total days
1 month, 0 days
SEE ALSO
DateTime::diff.
PHP Documentation Group DATEINTERVAL.FORMAT(3)
01-01-2013
