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Full Discussion: RAM Usage discrepancy
Operating Systems OS X (Apple) RAM Usage discrepancy Post 302749937 by dasx on Sunday 30th of December 2012 05:48:13 AM
Old 12-30-2012
RAM Usage discrepancy

Hey there! I'm a new user here who registered because I couldn't get these kind of questions answered in the place I directly com from. Smilie

I've found a discrepancy in total RAM used and I can't figure out why it is. My only guess is there are some RAM used by some stuff impossible to identify, but seems pretty unlikely to me.

From the beginning:
1. Launch Activity Monitor and sum the Active Memory + Wired Memory in the Memory tab. This'll give you some number of GB used. (User RAM + system RAM that is if I'm correct).
2. Order processes by RAM and sum their RAM usage. It's not even close. And I'm talking almost 30% off.

Launch terminal and run:
(did it quickly so it's probably a little bit redundant)
Code:
top -l1 -o RSIZE | sed 1,12d | awk '{print $11}' | sed -e 's/[+,-]//g' -e 's/K//g' -e 's/M/*1024/g' | bc
  | awk '{RAM+=$1} END {printf "\nProcesses RAM:\t%.2fGB\n",RAM/1024/1024}';
active=`vm_stat | grep ' active' | awk '{print $3}'`;
wired=`vm_stat | grep wired | awk '{print $4}'`;
echo   $wired $active | awk '{printf "RAM Usage:\t%.2fGB\n\n",($1+$2)*4096/1024/1024/1024}'

It'll print out the total amount of RAM used by processes and then the active + wired RAM.

(See my example in the attached image. As you can see there's around a 25% off in this case).

Any ideas why this happens?
RAM Usage discrepancy-captura-de-pantalla-2012-12-20-la-174227png

Last edited by Scott; 12-30-2012 at 07:05 AM.. Reason: Format code
 

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bcopy(9F)						   Kernel Functions for Drivers 						 bcopy(9F)

NAME
bcopy - copy data between address locations in the kernel SYNOPSIS
#include <sys/types.h> #include <sys/sunddi.h> void bcopy(const void *from, void *to, size_t bcount); INTERFACE LEVEL
Architecture independent level 1 (DDI/DKI). PARAMETERS
from Source address from which the copy is made. to Destination address to which copy is made. bcount The number of bytes moved. DESCRIPTION
bcopy() copies bcount bytes from one kernel address to another. If the input and output addresses overlap, the command executes, but the results may not be as expected. Note that bcopy() should never be used to move data in or out of a user buffer, because it has no provision for handling page faults. The user address space can be swapped out at any time, and bcopy() always assumes that there will be no paging faults. If bcopy() attempts to access the user buffer when it is swapped out, the system will panic. It is safe to use bcopy() to move data within kernel space, since kernel space is never swapped out. CONTEXT
bcopy() can be called from user or interrupt context. EXAMPLES
Example 1: Copying data between address locations in the kernel: An I/O request is made for data stored in a RAM disk. If the I/O operation is a read request, the data is copied from the RAM disk to a buffer (line 8). If it is a write request, the data is copied from a buffer to the RAM disk (line 15). bcopy() is used since both the RAM disk and the buffer are part of the kernel address space. 1 #define RAMDNBLK 1000 /* blocks in the RAM disk */ 2 #define RAMDBSIZ 512 /* bytes per block */ 3 char ramdblks[RAMDNBLK][RAMDBSIZ]; /* blocks forming RAM /* disk ... 4 5 if (bp->b_flags & B_READ) /* if read request, copy data */ 6 /* from RAM disk data block */ 7 /* to system buffer */ 8 bcopy(&ramdblks[bp->b_blkno][0], bp->b_un.b_addr, 9 bp->b_bcount); 10 11 else /* else write request, */ 12 /* copy data from a */ 13 /* system buffer to RAM disk */ 14 /* data block */ 15 bcopy(bp->b_un.b_addr, &ramdblks[bp->b_blkno][0], 16 bp->b_bcount); SEE ALSO
copyin(9F), copyout(9F) Writing Device Drivers WARNINGS
The from and to addresses must be within the kernel space. No range checking is done. If an address outside of the kernel space is selected, the driver may corrupt the system in an unpredictable way. SunOS 5.10 4 August 2003 bcopy(9F)
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