Hi I have two arrays :
@arcb= (450,625,720,645);
@arca=(625,645);
I need to remove the elements of @arca from elements of @arcb so that the content of @arcb will be (450,720).
Can anyone sugget me how to perform this operation?
The code I have used is this :
Code:
my @arcb= (450,625,720,645);
my @arca=(625,645);
foreach my $a (@arca){
for(my $i=0;$i<scalar(@arcb);$i++){
delete $arcb[$i] if($a==$arcb[$i]);
}
}
my $length = @arcb;
print "@arcb";
print "length is $length \n";
The problem is when I used this ,the length of the array is not changing even after the deletion
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Discussion started by: mohtashims
8 Replies
LEARN ABOUT SUSE
frexp
FREXP(3) Linux Programmer's Manual FREXP(3)NAME
frexp, frexpf, frexpl - convert floating-point number to fractional and integral components
SYNOPSIS
#include <math.h>
double frexp(double x, int *exp);
float frexpf(float x, int *exp);
long double frexpl(long double x, int *exp);
Link with -lm.
Feature Test Macro Requirements for glibc (see feature_test_macros(7)):
frexpf(), frexpl(): _BSD_SOURCE || _SVID_SOURCE || _XOPEN_SOURCE >= 600 || _ISOC99_SOURCE; or cc -std=c99
DESCRIPTION
The frexp() function is used to split the number x into a normalized fraction and an exponent which is stored in exp.
RETURN VALUE
The frexp() function returns the normalized fraction. If the argument x is not zero, the normalized fraction is x times a power of two,
and its absolute value is always in the range 1/2 (inclusive) to 1 (exclusive), that is, [0.5,1).
If x is zero, then the normalized fraction is zero and zero is stored in exp.
If x is a NaN, a NaN is returned, and the value of *exp is unspecified.
If x is positive infinity (negative infinity), positive infinity (negative infinity) is returned, and the value of *exp is unspecified.
ERRORS
No errors occur.
CONFORMING TO
C99, POSIX.1-2001. The variant returning double also conforms to SVr4, 4.3BSD, C89.
EXAMPLE
The program below produces results such as the following:
$ ./a.out 2560
frexp(2560, &e) = 0.625: 0.625 * 2^12 = 2560
$ ./a.out -4
frexp(-4, &e) = -0.5: -0.5 * 2^3 = -4
Program source
#include <math.h>
#include <float.h>
#include <stdio.h>
#include <stdlib.h>
int
main(int argc, char *argv[])
{
double x, r;
int exp;
x = strtod(argv[1], NULL);
r = frexp(x, &exp);
printf("frexp(%g, &e) = %g: %g * %d^%d = %g
",
x, r, r, FLT_RADIX, exp, x);
exit(EXIT_SUCCESS);
} /* main */
SEE ALSO ldexp(3), modf(3)COLOPHON
This page is part of release 3.25 of the Linux man-pages project. A description of the project, and information about reporting bugs, can
be found at http://www.kernel.org/doc/man-pages/.
2008-10-29 FREXP(3)
12-28-2012
Removing elements from an array
