Sponsored Content
Top Forums Shell Programming and Scripting HPUX find string in directory and filetype and replace string Post 302744341 by pure_jax on Friday 14th of December 2012 08:07:37 AM
Old 12-14-2012
HPUX find string in directory and filetype and replace string

Hi,

Here's my dilemma.

I need to replace the string Sept_2012 to Oct_2012 in all *config.py files within the current directory and below directories

Is this possible?

Also I am trying to find all instances of the string Sept_2012 within files in the current directory and below

I have scoured the forum and have found the following commands but cannot get any to do what ISmilieSmilie am trying to do Smilie
Code:
	  grep -rl 'Sept_2012' ./ | xargs sed -i 's/Sept_2012/Oct_2012/g'
	  
	  sed '/Sept_2012/ {n; s/Sept_2012/Oct_2012/;}'

	  awk '/Sept_2012/{x++}x{sub("Sept_2012","Oct_2012")&&x++&&x=(x==2)?0:x}1' infile
	  
	  cat sample.txt | sed -e "s/$SEARCH/$REPLACE/" >> result.txt
	  
	  perl -p -i -e 's/original text string/replacementstring/g' file


Last edited by Franklin52; 12-14-2012 at 09:22 AM.. Reason: Please use code tags for data and code samples
 

10 More Discussions You Might Find Interesting

1. Programming

how to find and replace string

hi I wanted to find this char " ^M " in my file and replace it with blank space. I am using Unix system. If i give command " :%s/^M//gc " it wont work so can anyone tell what is command to find and replace thankx (3 Replies)
Discussion started by: mridula
3 Replies

2. UNIX for Dummies Questions & Answers

Find and replace character in a string

Hi all, My problem is the following: I've a script that must list all files in a directory and write this information in a text file. I've tried to get the list through ls command and then write it using msgecho msgecho "`ls $PATH_APS_JOB_ORA`" This works good but the created string... (7 Replies)
Discussion started by: callimaco0082
7 Replies

3. Shell Programming and Scripting

find and replace string in a directory files

Hi, I have a directory has DIR1 and the D1 directory has 200+ files. I want change the string from "Bangalore" to "Bangaluru" in all files in the D1 directory. Thanks (2 Replies)
Discussion started by: koti_rama
2 Replies

4. Shell Programming and Scripting

Find the position of a string and replace with another string

Hi, I have a file named "Test_2008_01_21" The file contains a string "manual" that occurs many times in the file How can i find the positions of the string "manual" in the file Ex: if the string " manual " occurs three times in the file. i want to replace the second occurance of string... (6 Replies)
Discussion started by: bab123
6 Replies

5. Shell Programming and Scripting

Replace a string in all files under a directory and its subdirectories

Hello Friends, I've been trying to write a script which finds a string and change it with another string. For this i want to search all files (with its arguments) under a spesific directory and its subdirectories. For example lets assume i want to replace an IP= 192.168.0.4 with another... (4 Replies)
Discussion started by: EAGL€
4 Replies

6. Shell Programming and Scripting

Replace last 2 folder directory string with sed

Hi guys, I´m trying to replace the 2 last folders name in a list of directories with a new string, but I´m don´t know which regex to apply. Directories list: C/my user/documents/games & music C/my user/documents/photos 09-24-2008 C/my user/settings/config ?1_2 * The last folder may have... (11 Replies)
Discussion started by: cgkmal
11 Replies

7. Shell Programming and Scripting

sed or awk command to replace a string pattern with another string based on position of this string

here is what i want to achieve... consider a file contains below contents. the file size is large about 60mb cat dump.sql INSERT INTO `table1` (`id`, `action`, `date`, `descrip`, `lastModified`) VALUES (1,'Change','2011-05-05 00:00:00','Account Updated','2012-02-10... (10 Replies)
Discussion started by: vivek d r
10 Replies

8. Shell Programming and Scripting

find string and replace with string in other file

Dear all, I need your help, I have file like this: file1:23456 01910964830098775635 34567 01942809546554654323 67589 26546854368698023653 09778 58716868568576876878 08675 86178546154065406546 08573 54165843543054354305 . .file2: 23456 25 34567 26 67589 27 (2 Replies)
Discussion started by: attila
2 Replies

9. Solaris

How to find and replace a string?

Dear All I need to find and replace a string in a set of files. I try as : #find / -name "*"|xargs grep "Tektra"|grep -v "Tektra GSM BTS" But it doesn't work. It just finds the string in the files. I need to find and replace it.Can you please let me know how to correct it? Thank you (2 Replies)
Discussion started by: hadimotamedi
2 Replies

10. UNIX for Dummies Questions & Answers

Find and Replace string in UNIX

Hi All, Greetings. I have a .dat file which somewhere in its content contains symbol ""^ I want to replace it with "^ I tried with SED command but could not achieve what i wanted sed -e "s/'""^'/'"^'/ig" filename.dat (5 Replies)
Discussion started by: MaddyS
5 Replies
regex(1F)                                                          FMLI Commands                                                         regex(1F)

NAME
regex - match patterns against a string SYNOPSIS
regex [-e] [ -v "string"] [ pattern template] ... pattern [template] DESCRIPTION
The regex command takes a string from the standard input, and a list of pattern / template pairs, and runs regex() to compare the string against each pattern until there is a match. When a match occurs, regex writes the corresponding template to the standard output and returns TRUE. The last (or only) pattern does not need a template. If that is the pattern that matches the string, the function simply returns TRUE. If no match is found, regex returns FALSE. The argument pattern is a regular expression of the form described in regex(). In most cases, pattern should be enclosed in single quotes to turn off special meanings of characters. Note that only the final pattern in the list may lack a template. The argument template may contain the strings $m0 through $m9, which will be expanded to the part of pattern enclosed in ( ... )$0 through ( ... )$9 constructs (see examples below). Note that if you use this feature, you must be sure to enclose template in single quotes so that FMLI does not expand $m0 through $m9 at parse time. This feature gives regex much of the power of cut(1), paste(1), and grep(1), and some of the capabilities of sed(1). If there is no template, the default is $m0$m1$m2$m3$m4$m5$m6$m7$m8$m9. OPTIONS
The following options are supported: -e Evaluates the corresponding template and writes the result to the standard output. -v "string" Uses string instead of the standard input to match against patterns. EXAMPLES
Example 1: Cutting letters out of a string To cut the 4th through 8th letters out of a string (this example will output strin and return TRUE): `regex -v "my string is nice" '^.{3}(.{5})$0' '$m0'` Example 2: Validating input in a form In a form, to validate input to field 5 as an integer: valid=`regex -v "$F5" '^[0-9]+$'` Example 3: Translating an environment variable in a form In a form, to translate an environment variable which contains one of the numbers 1, 2, 3, 4, 5 to the letters a, b, c, d, e: value=`regex -v "$VAR1" 1 a 2 b 3 c 4 d 5 e '.*' 'Error'` Note the use of the pattern '.*' to mean "anything else". Example 4: Using backquoted expressions In the example below, all three lines constitute a single backquoted expression. This expression, by itself, could be put in a menu defini- tion file. Since backquoted expressions are expanded as they are parsed, and output from a backquoted expression (the cat command, in this example) becomes part of the definition file being parsed, this expression would read /etc/passwd and make a dynamic menu of all the login ids on the system. `cat /etc/passwd | regex '^([^:]*)$0.*$' ' name=$m0 action=`message "$m0 is a user"`'` DIAGNOSTICS
If none of the patterns match, regex returns FALSE, otherwise TRUE. NOTES
Patterns and templates must often be enclosed in single quotes to turn off the special meanings of characters. Especially if you use the $m0 through $m9 variables in the template, since FMLI will expand the variables (usually to "") before regex even sees them. Single characters in character classes (inside []) must be listed before character ranges, otherwise they will not be recognized. For exam- ple, [a-zA-Z_/] will not find underscores (_) or slashes (/), but [_/a-zA-Z] will. The regular expressions accepted by regcmp differ slightly from other utilities (that is, sed, grep, awk, ed, and so forth). regex with the -e option forces subsequent commands to be ignored. In other words, if a backquoted statement appears as follows: `regex -e ...; command1; command2` command1 and command2 would never be executed. However, dividing the expression into two: `regex -e ...``command1; command2` would yield the desired result. ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +-----------------------------+-----------------------------+ |Availability |SUNWcsu | +-----------------------------+-----------------------------+ SEE ALSO
awk(1), cut(1), grep(1), paste(1), sed(1), regcmp(3C), attributes(5) SunOS 5.10 12 Jul 1999 regex(1F)
All times are GMT -4. The time now is 09:57 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy