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Top Forums Shell Programming and Scripting Double quotes and variable proble in echo Post 302743947 by Corona688 on Thursday 13th of December 2012 03:06:21 PM
Old 12-13-2012
I think your nawk is missing the last '.

Code:
cat <<"EOF" >> filename
lpd | grep AL | nawk '{print "1dLA - " $0}'
EOF

Note the last EOF must be at the beginning of the line, not indented.
 

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recordio(1)                                                   General Commands Manual                                                  recordio(1)

NAME
recordio - record the input and output of a program SYNTAX
recordio program [ arg ... ] DESCRIPTION
recordio runs program with the given arguments. It prints lines to stderr showing the input and output of program. At the beginning of each line on stderr, recordio inserts the program process ID, along with < for input or > for output. At the end of each line it inserts a space, a plus sign, or [EOF]; a space indicates that there was a newline in the input or output, and [EOF] indicates the end of input or output. recordio prints every packet of input and output immediately. It does not attempt to combine packets into coherent stderr lines. For example, recordio sh -c 'cat /dev/fd/8 2>&1' > /dev/null could produce 5135 > cat: /dev/fd/8: Bad file descriptor 5135 > [EOF] or 5135 > cat: + 5135 > /dev/fd/8+ 5135 > : + 5135 > Bad file descriptor 5135 > [EOF] recordio uses several lines for long packets to guarantee that each line is printed atomically to stderr. recordio runs as a child of program. It exits when it sees the end of program's output. SEE ALSO
tcpserver(1) recordio(1)
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