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Full Discussion: Create user if UID not exist; else, exit the script
Top Forums Shell Programming and Scripting Create user if UID not exist; else, exit the script Post 302742999 by Scott on Wednesday 12th of December 2012 02:52:03 AM
Old 12-12-2012
Quote:
Originally Posted by itkamaraj
what you mean by cant save to variable ?

UID is the variable which has the user id.

Code:
 
RESULT=$(awk -F: -v U="$UID" '$3==UID {print "yes";exit}')
 
[ -z $RESULT ] && echo "Already Exists..Exiting..." && exit 1
#else your code goes here...
.....
.....

I think you forgot something important for your awk Smilie
This User Gave Thanks to Scott For This Post:
itkamaraj
 

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LEARN ABOUT DEBIAN

pam_rootok

PAM_ROOTOK(8)							 Linux-PAM Manual						     PAM_ROOTOK(8)

NAME

       pam_rootok - Gain only root access

SYNOPSIS

       pam_rootok.so [debug]

DESCRIPTION

       pam_rootok is a PAM module that authenticates the user if their UID is 0. Applications that are created setuid-root generally retain the
       UID of the user but run with the authority of an enhanced effective-UID. It is the real UID that is checked.

OPTIONS

       debug
	   Print debug information.

MODULE TYPES PROVIDED

       The auth, acct and password module types are provided.

RETURN VALUES

       PAM_SUCCESS
	   The UID is 0.

       PAM_AUTH_ERR
	   The UID is not 0.

EXAMPLES

       In the case of the su(1) application the historical usage is to permit the superuser to adopt the identity of a lesser user without the use
       of a password. To obtain this behavior with PAM the following pair of lines are needed for the corresponding entry in the /etc/pam.d/su
       configuration file:

	   # su authentication. Root is granted access by default.
	   auth  sufficient   pam_rootok.so
	   auth  required     pam_unix.so

SEE ALSO

       su(1), pam.conf(5), pam.d(5), pam(7)

AUTHOR

       pam_rootok was written by Andrew G. Morgan, <morgan@kernel.org>.

Linux-PAM Manual						    06/04/2011							     PAM_ROOTOK(8)
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