12-11-2012
So now -999.xx is missing data? In your first sample it was -999 indicating missing data.
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
Hello,
Please can someone help me in getitng last 7 days from the current date?
for eg:
input /default : today (10/18/2004)
required output:
10/17/2004
10/16/2004
10/15/2004
10/14/2004
10/13/2004
... (6 Replies)
Discussion started by: Anamika
6 Replies
2. Shell Programming and Scripting
Looking for some help on capturing the number of days in a month to set as a loop counter. Any ideas, please let me know. (3 Replies)
Discussion started by: flounder
3 Replies
3. UNIX for Dummies Questions & Answers
Hi,
I'm a newbie to unix and i'm loving every bit of it.
I need assistance in setting my date function in my script to "new month".
What I want to do is define the "newmonth" as the 1st of every month so my script can run by this time evry month through the year.
Can someone assist.
... (1 Reply)
Discussion started by: Agent704
1 Replies
4. Shell Programming and Scripting
does any one have any ideas how i would go about calculating the number of days left in the month from a bash script ?. I want to do some operations on a csv file according to the result (8 Replies)
Discussion started by: dunryc
8 Replies
5. Shell Programming and Scripting
im trying to do this inside a bash script;
for ((a=$COLUMNS;a>0;a--))
do
printf "="
done
printf "\n"
With it i want to display an "equals" line as long as de curent shell window.
but i can't get the $COLUMNS variable from the set enviroment.
Some help please. (2 Replies)
Discussion started by: Tártaro
2 Replies
6. Shell Programming and Scripting
Hi all. I am scripting in a POSIX shell on HPUX.
I am running a script that needs to determine the number of days in a month.
I found this on the forum and it works great:
X=`cal $(date +%m) $(date +%Y) | grep -v '' | wc -w`
The issue is that I am running the script on the 7th day of... (11 Replies)
Discussion started by: lyoncc
11 Replies
7. Shell Programming and Scripting
Hi,
I have an issue in date processing, the issue is I have a month as an int ( 1 - 12 ), the weekday as int ( 0 - 6 , 0 = Sunday), and the week day in month as int ( 0 - 5, 5 = last ex: first sunday, last monday, third tuesday ... ), now from those three parameters is there a possible way to... (5 Replies)
Discussion started by: modn3
5 Replies
8. Shell Programming and Scripting
hi all
searched google and here, cant find and am begining to suspect there is no options for this.
shell = born
with either the date or cal command I need to display the number of days in current month. can anyone point me in the right direction? (10 Replies)
Discussion started by: rontopia
10 Replies
9. UNIX for Dummies Questions & Answers
#!/bin/ksh
day=1
month=1
year=2012
if then
then
prevmonth=31
elif
then
prevmonth=30
elif
then
then prevmonth=29
elif
then prevmonth=29
else
prevmonth=28
fi (4 Replies)
Discussion started by: vagar11
4 Replies
10. Shell Programming and Scripting
I have a homework assignment:
----------------------------------------
"Display" the number of days in the current month. For example:
September 1996 has 30 days
----------------------------------------
I am trying to just display the head of cal to start the sentence.
eg. cal | head
... (1 Reply)
Discussion started by: eaafuddy
1 Replies
LEARN ABOUT CENTOS
timerisset
TIMERADD(3) Linux Programmer's Manual TIMERADD(3)
NAME
timeradd, timersub, timercmp, timerclear, timerisset - timeval operations
SYNOPSIS
#include <sys/time.h>
void timeradd(struct timeval *a, struct timeval *b,
struct timeval *res);
void timersub(struct timeval *a, struct timeval *b,
struct timeval *res);
void timerclear(struct timeval *tvp);
int timerisset(struct timeval *tvp);
int timercmp(struct timeval *a, struct timeval *b, CMP);
Feature Test Macro Requirements for glibc (see feature_test_macros(7)):
All functions shown above: _BSD_SOURCE
DESCRIPTION
The macros are provided to operate on timeval structures, defined in <sys/time.h> as:
struct timeval {
time_t tv_sec; /* seconds */
suseconds_t tv_usec; /* microseconds */
};
timeradd() adds the time values in a and b, and places the sum in the timeval pointed to by res. The result is normalized such that
res->tv_usec has a value in the range 0 to 999,999.
timersub() subtracts the time value in b from the time value in a, and places the result in the timeval pointed to by res. The result is
normalized such that res->tv_usec has a value in the range 0 to 999,999.
timerclear() zeros out the timeval structure pointed to by tvp, so that it represents the Epoch: 1970-01-01 00:00:00 +0000 (UTC).
timerisset() returns true (nonzero) if either field of the timeval structure pointed to by tvp contains a nonzero value.
timercmp() compares the timer values in a and b using the comparison operator CMP, and returns true (nonzero) or false (0) depending on the
result of the comparison. Some systems (but not Linux/glibc), have a broken timercmp() implementation, in which CMP of >=, <=, and == do
not work; portable applications can instead use
!timercmp(..., <)
!timercmp(..., >)
!timercmp(..., !=)
RETURN VALUE
timerisset() and timercmp() return true (nonzero) or false (0).
ERRORS
No errors are defined.
CONFORMING TO
Not in POSIX.1-2001. Present on most BSD derivatives.
SEE ALSO
gettimeofday(2), time(7)
COLOPHON
This page is part of release 3.53 of the Linux man-pages project. A description of the project, and information about reporting bugs, can
be found at http://www.kernel.org/doc/man-pages/.
Linux 2010-02-25 TIMERADD(3)