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Full Discussion: Recursive find / grep within a file / count of a string
Top Forums Shell Programming and Scripting Recursive find / grep within a file / count of a string Post 302738629 by Don Cragun on Sunday 2nd of December 2012 06:40:13 AM
Old 12-02-2012
Quote:
Originally Posted by RudiC
Thank you, Don, for commenting on my proposal.


At least with the combination of find and awk implemented on my linux system, there's a full path listing avalable, including filenames containing spaces:
Code:
find /var/log -iname \*.log -print0 |xargs -0 awk  -F\| 'FNR==1 {print FILENAME, NF}'
/var/log/auth.log 1
/var/log/dist-upgrade/history.log 0
. . .
/var/log/x y.log 3
/var/log/kern.log 1

Hi Rudi,
Yes, but note that by skipping the -print (or -print0) and the invocation of xargs, awk is still given the full pathname as an operand (even if there are spaces, tabs, or newlines included in the pathname).
Quote:
Yes. Still I thought the number of fields to be more relevant than the number of separators. Might have been premature.
Agreed. But it wasn't what Charlie6742 asked for.
Quote:

Works, and satisfies the standards, but:
Code:
time find . . . -print0 |xargs -0 awk  -F\| '. . .'
real    0m0.034s
time find . . . -exec awk -F\| '. . .' {} \;
real    0m0.208s

Not surprising since what you timed runs awk once for each input file.
But note that I specified:
Code:
find . . . -exec awk -F\| '. . .' {} +

not:
Code:
find . . . -exec awk -F\| '. . .' {} \;

With the + instead of the \; find shouldn't execute awk any more times than xargs would and we avoid needing to start xargs at all.
Quote:
Special thanks for this; I was looking for that or an equivalent; unfortunately not available on my system.
 

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