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Top Forums UNIX for Advanced & Expert Users [SOLVED] Code does not run when assigned to a variable Post 302738185 by in2nix4life on Friday 30th of November 2012 01:34:53 PM
Old 11-30-2012
Not sure what OS or shell you're using but the output might be a bit much for a normal variable. Instead, you could try storing the returned output in an array:

Code:
declare -a array=( $(su nbadmin -c "ssh -t servery /usr/openv/netbackup/bin/bplist -C servery -t 19 -l -R -s 11/01/2012 -e 11/01/2012 /vol/root/") )

Then iterate the array to display the results:

for (( i = 0; i < ${#array[@]}; i++ ))
do
    echo ${array[$i]}
done

 

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KEY(3)									 1								    KEY(3)

key - Fetch a key from an array

SYNOPSIS
mixed key (array &$array) DESCRIPTION
key(3) returns the index element of the current array position. PARAMETERS
o $array - The array. RETURN VALUES
The key(3) function simply returns the key of the array element that's currently being pointed to by the internal pointer. It does not move the pointer in any way. If the internal pointer points beyond the end of the elements list or the array is empty, key(3) returns NULL. EXAMPLES
Example #1 key(3) example <?php $array = array( 'fruit1' => 'apple', 'fruit2' => 'orange', 'fruit3' => 'grape', 'fruit4' => 'apple', 'fruit5' => 'apple'); // this cycle echoes all associative array // key where value equals "apple" while ($fruit_name = current($array)) { if ($fruit_name == 'apple') { echo key($array).'<br />'; } next($array); } ?> The above example will output: fruit1<br /> fruit4<br /> fruit5<br /> SEE ALSO
current(3), next(3). PHP Documentation Group KEY(3)
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