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Full Discussion: While loop problem in C
Top Forums Programming While loop problem in C Post 302736853 by Raj 89 on Wednesday 28th of November 2012 04:47:59 AM
Old 11-28-2012
Quote:
Originally Posted by gabam

Code:
 

    int cont = 1;
 
    while( cont == 1 )   
    {
             printf( "Enter i\n" );
             scanf( "%d", &i );
 
             switch( i )
             {
                    case 1:
                              printf( "1\n" );  
                              cont = 0;
                              break;
                    case 2:
                              printf( "2\n" );
                              cont = 0;
                              break;
                    default:
                              printf( "Invalid value" );
             }
    }

Your program is working perfectly fine.I am not able to understand your logic clearly. What is that you are trying to do. You have normally written the while loop in such a way that it will be exited whenever the value of cont is other than 1. So at first the while loop satisfies and the user provides the input for "i".
But when you provide 1 or 2 for the switch case, the value const will be replaced with zero and then the execution goes to while. This will act as an infinite loop till the value of i tends to be other than 1 r 2 .
but if the value of i is other than 1 or 2, cont will be same and the while loop fails the second time.

---------- Post updated at 03:17 PM ---------- Previous update was at 03:15 PM ----------

Quote:
Originally Posted by gabam

Your code is replaced into this. Well this works better.

Code:
 
int main()
{
    int i = 0;
    int cont = 1;
 
    while( cont == 1 ) 
    {
             printf( "Enter i\n" );
             scanf( "%d", &i );
 
             switch( i )
             {
                    case 1:
                              printf( "1\n" );
                              break;
                    case 2:
                              printf( "2\n" );
                              break;
                    default:
                              printf( "Invalid value" );
                              cont = 0 ;
             }
    }
 
    return 0;
}

Maybe this could help you...
 

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Layout::Manager::Axis(3pm)				User Contributed Perl Documentation				Layout::Manager::Axis(3pm)

NAME
Layout::Manager::Axis - Compass-like resizing managers DESCRIPTION
Axis is very similar to Compass with one exception: Components added to the east and west consume space on the sides of of the north and south. Components at the north and south are resized when east and west components are added. +--------------------------------+ | x | north | x | +-----+--------------------+-----+ | | | | | w | | e | | e | center | a | | s | | s | | t | | t | | | | | +-----+--------------------+-----+ | x | south | x | +--------------------------------+ The x boxes above will effectively be dead-space. No components will occupy those areas. Why, you ask? Some components (such as axes on a chart, for which this manager is named) need to be the exact same hight or with as the center component. If the chart area is represented by the center area and an axis is positioned to the west, it needs to know how big the center is to accurately draw tick marks. SYNOPSIS
$cont->add_component($comp1, 'north'); $cont->add_component($comp2, 'east'); my $lm = Layout::Manager::Axis->new; $lm->do_layout($cont); POSITIONING
When you add a component with add_component the second argument should be one of: north, south, east, west or center. Case doesn't matter. You can also just provide the first letter of the word and it will do the same thing. METHODS
do_layout Size and position the components in this layout. AUTHOR
Cory Watson, "<gphat@cpan.org>" COPYRIGHT &; LICENSE Copyright 2008 - 2010 Cory G Watson This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself. perl v5.12.3 2011-05-16 Layout::Manager::Axis(3pm)
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