Hi,
There are lots of threads about how to manipulate the date using date +%m %.......
But how can I change the default format of the commad date?
$ date
Mon Apr 10 10:57:15 BST 2006
This would be on fedora and SunOs.
Cheers,
Neil (4 Replies)
Hi Experts,
Please help me to get the following from script for Unix ENvironment(shell, perl, tr, sed, awk).
INPUT FILE:
20K,ME,592971
20K,YOU,2
20K,HE,1244998
50K,YOU,480110
50K,ME,17
50K,HIS,10
50K,HE,1370391
OUTPUT FILE:
K,ME,YOU,HE,HIS
20K,592971,2,1244998,0... (5 Replies)
So I have a csv file where the 3rd field is a date string in the format yyyy-mm-dd. I need to change it to mm/dd/yyyy. So each line in the csv file looks like:
StringData,StringData,2009-02-17,12.345,StringData
StringData,StringData,2009-02-16,65.789,StringData
Any idea how I can keep... (5 Replies)
I have a list of dates in the following format: mm/dd/yyyy and want to change these to the MySQL standard format: yyyy-mm-dd.
The dates in the original file may or may not be zero padded, so April is sometimes "04" and other times simply "4".
This is what I use to change the format:
sed -i '' -e... (2 Replies)
Hi...
I have an inputfile name as :- abc_test_20120213.dat (date in yyyymmdd format)
I need the output file name as abc_test_13022012.dat (date in ddmmyyyy format)
Please help me on this...
Thanks in advance. (5 Replies)
Hi all,
I have a file with below data
af23b|11-FEB-12|acc7
ad23b|12-JAN-12|acc4
as23b|15-DEC-11|acc5
z123b|18-FEB-12|acc1
I need the output as below:-(date in yyyymmdd format)
af23b|20120211|acc7
ad23b|20120112|acc4
as23b|20111215|acc5
z123b|20120218|acc1
Please help me on this.... (7 Replies)
How can i make the date command output yesterday's date, current date and the date 4 days ago, in the following format:
2012-10-03
code:
date +% ???? (3 Replies)
Hi,
We have csv file where date is coming in MM/DD/YYYY HH:MM:SS (06/23/2015 20:59:12) in multiple places
But we need to change the date format to DD/Mon/YYYY HH:MM:SS (23/Jul/2015 20:59:12) using shell script.
Please let us know how can we achieve the same. (16 Replies)
Hi All,
I have a CSV file which is as below. Basically I need to take the year column in it and find if the year is >= 20152 . If that is then I should subtract all values by 6. In the below example in description I am having number mentioned as YYWW so I need to subtract those by -5. Whereever... (8 Replies)
Discussion started by: arunkumar_mca
8 Replies
LEARN ABOUT DEBIAN
ifpps
ifpps(8) netsniff-ng-toolkit ifpps(8)NAME
ifpps - fetch and format kernel network statistics
SYNOPSIS
ifpps -d|--dev <netdev> [-t|--interval <sec>][-p|--promisc][-c|--term]
[-C|--csv][-H|--csv-tablehead][-l|--loop][-v|--version][-h|--help]
DESCRIPTION
A tiny tool to provide top-like reliable networking statistics. ifpps reads out the 'real' kernel statistics, so it does not give
erroneous statistics on high I/O load.
OPTIONS
ifpps --dev eth0
Fetch eth0 interface statistics.
ifpps --dev eth0 --interval 60 --csv
Output eth0 interface statistics every minute in CSV format.
OPTIONS
-h|--help
Print help text and lists all options.
-v|--version
Print version.
-d|--dev <netdev>
Device to fetch statistics for i.e., eth0.
-p|--promisc
Put the device in promiscuous mode
-t|--interval <time>
Refresh time in sec (default 1 sec)
-c|--term
Output to terminal
-C|--csv
Output in CSV format. E.g. post-processing with Gnuplot et al.
-H|--csv-tablehead
Print CSV table head.
-l|--loop
Loop terminal output.
AUTHOR
Written by Daniel Borkmann <daniel@netsniff-ng.org>
DOCUMENTATION
Documentation by Emmanuel Roullit <emmanuel@netsniff-ng.org>
BUGS
Please report bugs to <bugs@netsniff-ng.org>
2012-06-29 ifpps(8)