Hi,
There are lots of threads about how to manipulate the date using date +%m %.......
But how can I change the default format of the commad date?
$ date
Mon Apr 10 10:57:15 BST 2006
This would be on fedora and SunOs.
Cheers,
Neil (4 Replies)
Hi Experts,
Please help me to get the following from script for Unix ENvironment(shell, perl, tr, sed, awk).
INPUT FILE:
20K,ME,592971
20K,YOU,2
20K,HE,1244998
50K,YOU,480110
50K,ME,17
50K,HIS,10
50K,HE,1370391
OUTPUT FILE:
K,ME,YOU,HE,HIS
20K,592971,2,1244998,0... (5 Replies)
So I have a csv file where the 3rd field is a date string in the format yyyy-mm-dd. I need to change it to mm/dd/yyyy. So each line in the csv file looks like:
StringData,StringData,2009-02-17,12.345,StringData
StringData,StringData,2009-02-16,65.789,StringData
Any idea how I can keep... (5 Replies)
I have a list of dates in the following format: mm/dd/yyyy and want to change these to the MySQL standard format: yyyy-mm-dd.
The dates in the original file may or may not be zero padded, so April is sometimes "04" and other times simply "4".
This is what I use to change the format:
sed -i '' -e... (2 Replies)
Hi...
I have an inputfile name as :- abc_test_20120213.dat (date in yyyymmdd format)
I need the output file name as abc_test_13022012.dat (date in ddmmyyyy format)
Please help me on this...
Thanks in advance. (5 Replies)
Hi all,
I have a file with below data
af23b|11-FEB-12|acc7
ad23b|12-JAN-12|acc4
as23b|15-DEC-11|acc5
z123b|18-FEB-12|acc1
I need the output as below:-(date in yyyymmdd format)
af23b|20120211|acc7
ad23b|20120112|acc4
as23b|20111215|acc5
z123b|20120218|acc1
Please help me on this.... (7 Replies)
How can i make the date command output yesterday's date, current date and the date 4 days ago, in the following format:
2012-10-03
code:
date +% ???? (3 Replies)
Hi,
We have csv file where date is coming in MM/DD/YYYY HH:MM:SS (06/23/2015 20:59:12) in multiple places
But we need to change the date format to DD/Mon/YYYY HH:MM:SS (23/Jul/2015 20:59:12) using shell script.
Please let us know how can we achieve the same. (16 Replies)
Hi All,
I have a CSV file which is as below. Basically I need to take the year column in it and find if the year is >= 20152 . If that is then I should subtract all values by 6. In the below example in description I am having number mentioned as YYWW so I need to subtract those by -5. Whereever... (8 Replies)
Discussion started by: arunkumar_mca
8 Replies
LEARN ABOUT SUSE
igawk
IGAWK(1) Utility Commands IGAWK(1)NAME
igawk - gawk with include files
SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ...
igawk [ all gawk options ] [ -- ] program-text file ...
DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1).
AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like
@include getopt.awk
in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path.
OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports.
EXAMPLES
cat << EOF > test.awk
@include getopt.awk
BEGIN {
while (getopt(ARGC, ARGV, "am:q") != -1)
...
}
EOF
igawk -f test.awk
SEE ALSO gawk(1)
Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995.
AUTHOR
Arnold Robbins (arnold@skeeve.com).
Free Software Foundation Nov 3 1999 IGAWK(1)