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Top Forums Shell Programming and Scripting awk & basename puzzler - advise sought Post 302732941 by Don Cragun on Monday 19th of November 2012 11:32:02 AM
Old 11-19-2012
Quote:
Originally Posted by davidra
Agma / Don

Many thanks for responding

I've tried both and I think the one that I more readily understand and has worked all OK is your contribution Don

Agma - apologies but didn't understand <source##*/>....the ##* bit but I did appreciate you taking the time to explain that I didn't need cat / while
Hi davidra,
I'm glad to hear that my contribution worked for you.

This is what ${source##*/} does: it looks at the shell variable named source and if its value matches the pattern */ (which matches any string that ends with a / character), it removes the longest match for that pattern from the start (left) of the string. If $source does not contain any / characters, it is expanded unchanged. Similarly, ${var#pattern} removes the shortest match for pattern from the start of the expansion of $var, ${var%pattern} removes the shortest match for pattern from the end of the expansion of $var, and ${var%%pattern} removes the longest match for pattern from the end of the expansion of $var. For example:
Code:
src="/usr/src/cmd.c"
echo X${src##*/}X X${src#*/}X X${src%/*}X X${src%%/*}X X${src%XYZ}X

produces the output:
Code:
Xcmd.cX Xusr/src/cmd.cX X/usr/srcX XX X/usr/src/cmd.cX

This User Gave Thanks to Don Cragun For This Post:
 

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