I need to figure out the numeric representation of the previous month (in an automated monthly-running script) so that I may append it to a filename. I have tried statements such as variable=`date +%m -1` (and several variations) but with no success. I have also tried simply assigning the value... (3 Replies)
hi gurus!
i realize that my question shows my stupidness, but i need your help!
i have:
s_date=`date +%m-%d-%Y_%I%p`
variable and i need the same, but minus one hour..
what i made:
s_date=time(`date +%m-%d-%Y_%I%p`) - 3600
but i'm getting:
daily_exports.sh: line 20: syntax error near... (4 Replies)
Hi all,
I need the date subtraction fuctionality using shell commands.
For example:
date1:Wed Apr 5 08:35:21 IST 2006
date2:Tue Apr 4 10:35:44 IST 2006
I need the date subtraction result like " 22 hours 23 seconds".
Please guide me to complete this task.
Can you please help me ASAP.
... (3 Replies)
hi,
i set up a script on my server to do a particular task once files from an external system are ftpd in the format compaq_20100110 (YYDDMM). Interestingly, the source of ftp is sending the files in the format e.g 20100109 i.e. previous date and for some reason this fails.kindly see my script... (2 Replies)
Hallo all i am trying to execute this script ...............
But this is throwing the error......
use of uninitialized value in subtraction in at icd_convert.pl line 156
use of uninitialized value in subtraction in at icd_convert.pl line 157
use of uninitialized value in subtraction in at... (1 Reply)
HI gurus...
I have a PERL file that help me extract the date and time
of the file.
The format of this is: yyyymmddhhmmss.
Example:
20100430070935 (April 30 2010 07:09:35)
How can i subtract the acquired time from system's time..??
The answer... (6 Replies)
Hi
#!/bin/sh
month=`date +%m`
year=`date +%Y`
echo $month
a=02
# Retaining Data for Current and Previous Month
lmonth=`expr $month - $a`
if test "$lmonth" = "0"
then
lmonth=12
year=`expr $year - 1`
fi
echo $year
echo $lmonth
The output is (3 Replies)
Hello all .
I have two arrays.
${ARRAY_MOUNT_POINT_CAPACITY}
${ARRAY_MOUNT_POINT_CAPACITY}.
Whats the synatx of subtracting their values , placing them in variable V1 and then echoeing it ???
Ive tried expr and let ...gives me ./test_code.sh: difference: bad number (3 Replies)
Hello All,
I am a newbie to unix shell scripting and need to write a script that displays the difference between two variables that stores date value.
For example,
F1=`ls -ltr file1* | tail -1 |tr -s ' ' |cut -d' ' -f6,7,8`
F2=`ls -ltr file2* | tail -1 |tr -s ' ' |cut -d' ' -f6,7,8`
F1... (3 Replies)
Discussion started by: priyaa2010
3 Replies
LEARN ABOUT SUSE
convertquota
CONVERTQUOTA(8) System Manager's Manual CONVERTQUOTA(8)NAME
convertquota - convert quota from old file format to new one
SYNOPSIS
convertquota [ -ug ] [ -e | -f ] filesystem
DESCRIPTION
convertquota converts old quota files quota.user and quota.group to files aquota.user and aquota.group in new format currently used by
2.4.0-ac? and newer or by SuSE or Red Hat Linux 2.4 kernels on filesystem.
New file format allows using quotas for 32-bit uids / gids, setting quotas for root, accounting used space in bytes (and so allowing use of
quotas in ReiserFS) and it is also architecture independent. This format introduces Radix Tree (a simple form of tree structure) to quota
file.
OPTIONS -u, --user
convert user quota file. This is the default.
-g, --group
convert group quota file.
-f, --convert-format
convert from old file format to new one. This is the default.
-e, --convert-endian
convert new file format from big endian to little endian.
-V, --version
print version information.
FILES
aquota.user new user quota file
aquota.group new group quota file
SEE ALSO quota(1), setquota(8), edquota(8), quotacheck(8), quotaon(8), repquota(8)AUTHOR
Jan Kara <jack@suse.cz>
4th Berkeley Distribution Fri Aug 20 1999 CONVERTQUOTA(8)