If you have the perl with Date::Calc module, then you can use Mktime to calculate the epoch. Then subtract the both epoch and divide it by 60 (seconds) to find the minutes.
Code:
$time = Mktime($year,$month,$day, $hour,$min,$sec);
you can retrieve the $year,$month....$sec by using the below
/(....)(..)(..)(..)(..)(..)/
I need to figure out the numeric representation of the previous month (in an automated monthly-running script) so that I may append it to a filename. I have tried statements such as variable=`date +%m -1` (and several variations) but with no success. I have also tried simply assigning the value... (3 Replies)
hi gurus!
i realize that my question shows my stupidness, but i need your help!
i have:
s_date=`date +%m-%d-%Y_%I%p`
variable and i need the same, but minus one hour..
what i made:
s_date=time(`date +%m-%d-%Y_%I%p`) - 3600
but i'm getting:
daily_exports.sh: line 20: syntax error near... (4 Replies)
Hi all,
I need the date subtraction fuctionality using shell commands.
For example:
date1:Wed Apr 5 08:35:21 IST 2006
date2:Tue Apr 4 10:35:44 IST 2006
I need the date subtraction result like " 22 hours 23 seconds".
Please guide me to complete this task.
Can you please help me ASAP.
... (3 Replies)
hi,
i set up a script on my server to do a particular task once files from an external system are ftpd in the format compaq_20100110 (YYDDMM). Interestingly, the source of ftp is sending the files in the format e.g 20100109 i.e. previous date and for some reason this fails.kindly see my script... (2 Replies)
Hallo all i am trying to execute this script ...............
But this is throwing the error......
use of uninitialized value in subtraction in at icd_convert.pl line 156
use of uninitialized value in subtraction in at icd_convert.pl line 157
use of uninitialized value in subtraction in at... (1 Reply)
HI gurus...
I have a PERL file that help me extract the date and time
of the file.
The format of this is: yyyymmddhhmmss.
Example:
20100430070935 (April 30 2010 07:09:35)
How can i subtract the acquired time from system's time..??
The answer... (6 Replies)
Hi
#!/bin/sh
month=`date +%m`
year=`date +%Y`
echo $month
a=02
# Retaining Data for Current and Previous Month
lmonth=`expr $month - $a`
if test "$lmonth" = "0"
then
lmonth=12
year=`expr $year - 1`
fi
echo $year
echo $lmonth
The output is (3 Replies)
Hello all .
I have two arrays.
${ARRAY_MOUNT_POINT_CAPACITY}
${ARRAY_MOUNT_POINT_CAPACITY}.
Whats the synatx of subtracting their values , placing them in variable V1 and then echoeing it ???
Ive tried expr and let ...gives me ./test_code.sh: difference: bad number (3 Replies)
Hello All,
I am a newbie to unix shell scripting and need to write a script that displays the difference between two variables that stores date value.
For example,
F1=`ls -ltr file1* | tail -1 |tr -s ' ' |cut -d' ' -f6,7,8`
F2=`ls -ltr file2* | tail -1 |tr -s ' ' |cut -d' ' -f6,7,8`
F1... (3 Replies)
Discussion started by: priyaa2010
3 Replies
LEARN ABOUT PHP
gmmktime
GMMKTIME(3) 1 GMMKTIME(3)gmmktime - Get Unix timestamp for a GMT dateSYNOPSIS
int gmmktime ([int $hour = gmdate("H")], [int $minute = gmdate("i")], [int $second = gmdate("s")], [int $month = gmdate("n")], [int
$day = gmdate("j")], [int $year = gmdate("Y")], [int $is_dst = -1])
DESCRIPTION
Identical to mktime(3) except the passed parameters represents a GMT date. gmmktime(3) internally uses mktime(3) so only times valid in
derived local time can be used.
Like mktime(3), arguments may be left out in order from right to left, with any omitted arguments being set to the current corresponding
GMT value.
PARAMETERS
o $hour
- The number of the hour relative to the start of the day determined by $month, $day and $year. Negative values reference the hour
before midnight of the day in question. Values greater than 23 reference the appropriate hour in the following day(s).
o $minute
- The number of the minute relative to the start of the $hour. Negative values reference the minute in the previous hour. Values
greater than 59 reference the appropriate minute in the following hour(s).
o $second
- The number of seconds relative to the start of the $minute. Negative values reference the second in the previous minute. Values
greater than 59 reference the appropriate second in the following minute(s).
o $month
- The number of the month relative to the end of the previous year. Values 1 to 12 reference the normal calendar months of the
year in question. Values less than 1 (including negative values) reference the months in the previous year in reverse order, so 0
is December, -1 is November, etc. Values greater than 12 reference the appropriate month in the following year(s).
o $day
- The number of the day relative to the end of the previous month. Values 1 to 28, 29, 30 or 31 (depending upon the month) refer-
ence the normal days in the relevant month. Values less than 1 (including negative values) reference the days in the previous
month, so 0 is the last day of the previous month, -1 is the day before that, etc. Values greater than the number of days in the
relevant month reference the appropriate day in the following month(s).
o $year
- The year
o $is_dst
- Parameters always represent a GMT date so $is_dst doesn't influence the result.
Note
This parameter has been removed in PHP 7.0.0.
RETURN VALUES
Returns a integer Unix timestamp.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 7.0.0 | |
| | |
| | $is_dst parameter has been removed. |
| | |
| 5.1.0 | |
| | |
| | As of PHP 5.1.0, the $is_dst parameter became |
| | deprecated. As a result, the new timezone han- |
| | dling features should be used instead. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
gmmktime(3) basic example
<?php
// Prints: July 1, 2000 is on a Saturday
echo "July 1, 2000 is on a " . date("l", gmmktime(0, 0, 0, 7, 1, 2000));
?>
SEE ALSO mktime(3), date(3), time(3).
PHP Documentation Group GMMKTIME(3)