If your "ENCRYPT" command encrypts the file named by its 1st argument and stores the results in a file in the current directory with the same name, this should do what you want:
This is written using the Korn shell, but will work with any shell that accepts basic Bourne shell syntax (i.e., not csh or similar shells).
If you don't happen to be in the directory where the source file is located, passing the basename of the source file to ENCRYPT won't allow it to find your source file.
This User Gave Thanks to Don Cragun For This Post:
The Web-based contact form on my site has been under distributed spamming attacks for nearly a month already. Obviously, a spammer has tried to generate HTTP requests containing ads to male drugs and all sorts of similar stuff directly to the form mail processor script on my site using a robot, as... (5 Replies)
Hi,
I am using the following command to extract any log files that are older than 3 days using the following command.
find DIR/LOGDIR -type f -mtime +3 |grep LOG > log_list.out
The results are
DIR/LOGDIR/1.LOG
DIR/LOGDIR/2.LOG
DIR/LOGDIR/3.LOG
DIR/LOGDIR/4.LOG
How do inculde (basename... (4 Replies)
hi if we have to use basename how can we do this in awk?
did the below but is not working..
psg -t "?"| awk '{
command=($5 ~ /^/)? $9:$8
# cmd_name=`basename $command` (gives error)
system("basename $command >>... (10 Replies)
Hi Experts,
I am adding a column of numbers with awk , however not getting correct output:
# awk '{sum+=$1} END {print sum}' datafile
2.15291e+06
How can I getthe output like : 2152910
Thank you..
# awk '{sum+=$1} END {print sum}' datafile
2.15079e+06 (3 Replies)
I am having a hard time extracting the file name from the above code. Instead of printing /folder/file.1$.5$, I would like it to print the file name file.1$.5$.
I have tried using basename but it looks like NAWK or AWK does not recognise basename. Each time I type it in, it prints out the word... (4 Replies)
Hi gurus,
i need your advise on how to process this file using awk.
i have this file
COLA COLB COLC COLD COLE COLF COLG COLH
AAAA 86 111 122 133 144 155 266 377
BBBB 70 211 222 233 244 255 266 ... (6 Replies)
im trying to extract the basename of a process running on a host
processx is running at host1 as /applications/myapps/bin/processx
i wanted to check if its running, then extract the basename only using:
$ ssh host1 "ps aux | grep -v 'grep' | grep 'processx'" | awk '{ print basename $11}'
... (10 Replies)
Here is a very simple Korn shell script running on an AIX 5.3 box.
Why does this work without the $ prepended to RET_CD?
#!/bin/ksh
RET_CD=0
if &&
then
echo "RET_CD is not 0 and not 2"
else
echo "RET_CD is a 0 or a 2"
fi (3 Replies)
I'm using solaris 10
Scenario as follows
I have a logfile with 2 columns:
column 1 = source directory + filename
column 2 = destination directory + filename
Using cron, my script polls for new files and adds them to the logfile ($ELOG) as described above. Using sed, the distination... (2 Replies)
Hi Guru's.
I am trying to use to check if $5 is greater than 80 & if not 100, then to print $0 :
awk '{ if ($5>80) && if ($5 != 100) print $0}
But getting error:
>bdf1|sed 's/%//g'|awk '{ if ($5>80) && if ($5 != 100) print $0}'
syntax error The source line is 1.
The error... (6 Replies)
Discussion started by: rveri
6 Replies
LEARN ABOUT LINUX
shtool-path
SHTOOL-PATH.TMP(1) GNU Portable Shell Tool SHTOOL-PATH.TMP(1)NAME
shtool-path - GNU shtool command dealing with shell path variables
SYNOPSIS
shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...]
DESCRIPTION
This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments. It
prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found.
OPTIONS
The following command line options are available.
-s, --suppress
Supress output. Useful to only test whether a program exists with the help of the return code.
-r, --reverse
Transform a forward path to a subdirectory into a reverse path.
-d, --dirname
Output the directory name of str.
-b, --basename
Output the base name of str.
-m, --magic
Enable advanced magic search for ""perl"" and ""cpp"".
-p, --path path
Search in path. Default is to search in $PATH.
EXAMPLE
# shell script
awk=`shtool path -p "${PATH}:." gawk nawk awk`
perl=`shtool path -m perl`
cpp=`shtool path -m cpp`
revpath=`shtool path -r path/to/subdir`
HISTORY
The GNU shtool path command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken
over into GNU shtool.
SEE ALSO shtool(1), which(1).
18-Jul-2008 shtool 2.0.8 SHTOOL-PATH.TMP(1)