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Full Discussion: [Solved] Using w; how to list find all the users
Top Forums UNIX for Dummies Questions & Answers [Solved] Using w; how to list find all the users Post 302730775 by alister on Tuesday 13th of November 2012 03:42:35 PM
Old 11-13-2012
Quote:
Originally Posted by samnyc
Code:
w |more
 16:06:52 up 568 days, 21:26, 75 users,  load average: 0.07, 0.10, 0.05
USER     TTY      FROM              LOGIN@   IDLE   JCPU   PCPU WHAT
sak pts/1    :37.0            21Feb12 263days  0.18s  0.18s -csh
apr pts/3    -                Tue18    4days  0.07s  0.07s -bin/tcsh
sshe  pts/4    -                18Oct12 25days  0.00s  7:34  kdeinit: kded 
xzha   pts/6    -                Fri17    0.00s  0.69s  0.58s -bin/tcsh
xzha   pts/7    -                Wed10    5days  0.00s 10.63s kdeinit: kded 
peter    pts/9    :24.0            13:45    2:20m 52.80s  0.09s -csh
sshe  pts/12   -                19Oct12 24days  0.15s  0.03s -bin/tcsh
sshe  pts/13   -                19Oct12 24days  0.00s  7:39  kdeinit: kded 
sshe  pts/15   -                19Oct12 24da

Quote:
Originally Posted by bipinajith
Code:
w | awk '!/PCPU/ && !/days/ { print $1 } ' | sort -u

That's not a reliable approach. If all of a user's sessions have been idle for a while, they will not be listed because !/days/ would exclude them all. The same condition will also exclude any sessions currently running a command line which includes "days". Any username in which the string "days" appears is also similarly doomed.

Similar issues apply to the use of !/PCPU/.

In my opinion, a much more robust solution would specifically exclude the header:
Code:
w | awk 'NR>2 {print $1} | sort -u

Regards,
Alister
These 2 Users Gave Thanks to alister For This Post:
samnyc Yoda
 

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