I have a large csv file that looks like this:
The 3rd field is a unix time stamp that I want to convert to human readable.
I wrote a bash script with this code:
IFS=$','
cat $1 | while read ID user DATE text flags read; do
echo -e "$ID,$user,$(date -d @$DATE),$text,$flags,$read... (3 Replies)
Below is the format of my file which consist of
1)BSB
2)BSB/ADS
3)CIB
4)CIB/CRH
5)CIB/DCC
6)CIB/EMD
7)CIB/GDSPresentation
8)CIB/HCH
9)CIB/HSM
10)CIB/MCH
11)CIB/RCH
12)COB
13)DCI
14)DIB
15)DIB/H2H
16)DIB/HotelSync
17)DIB/UADBA (11 Replies)
Hi,
Is there any short method to print from a particular field till another filed using awk?
Example File:
File1
====
1|2|acv|vbc|......|100|342
2|3|afg|nhj|.......|100|346
Expected output:
File2
====
acv|vbc|.....|100
afg|nhj|.....|100 (8 Replies)
Hi !
input:
111|222|333|aaa|bbb|ccc
999|888|777|nnn|kkk
444|666|555|eee|ttt|ooo|ppp
With awk, I am trying to change the FS "|" to "; " only from the 4th field until the end (the number of fields vary between records).
In order to get:
111|222|333|aaa; bbb; ccc
999|888|777|nnn; kkk... (1 Reply)
How do I do the product of nth filed just like sum. For sum I know like
awk '{ sum += $12 } END {printf "%.2f\n", sum}'
works as initial sum = 0.
But for product how do initialize the variable to 1? (2 Replies)
Hello
I was working on a script where the output of my file is
1234
4567
8973
43214
78965
I need the value in below format of this file.The nth field should have space instead of ,(comma)
1234,4567,8973,43214 78965
I tried the code but not working completely
xargs <temp_PP.7250... (3 Replies)
Using Awk, how can I achieve the following?
I have set of record numbers, for which, I have to replace the nth field with some values, say spaces.
Eg:
Set of Records : 4,9,10,55,89,etc
I have to change the 8th field of all the above set of records to spaces (10 spaces).
Its a delimited... (1 Reply)
I have posted this again as old post is closed and I am not able to reopen. so please consider this new post
Input File :
1,A,Completed,06.02_19.36,Jun 30 20:00
2,BBB,Failed,07.04_05.12,Jul 21 19:06
3,CCCCC,New,07.21_03.03,Jul 26 12:57
4,DDDDD,Pending,,
I wast output file as:
... (7 Replies)
Hi,
I have two (2) things that I want to do.
First is to change the date format that is in the nth field from MM/DD/YY to YY/MM/DD. Preferably, I wish I know how to make it a 4-digit year but I don't. Problem is I can only assume it is a 20 century
Second is somehow know how to figure out... (1 Reply)
For some reason I am having difficulty performing what should be a fairly easy task. I would like to print lines of a file that have a unique value in the first field. For example, I have a large data-set with the following excerpt:
PS003,001 MZMWR/ L-DWD// *
PS003,001... (4 Replies)
Discussion started by: jvoot
4 Replies
LEARN ABOUT REDHAT
igawk
IGAWK(1) Utility Commands IGAWK(1)NAME
igawk - gawk with include files
SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ...
igawk [ all gawk options ] [ -- ] program-text file ...
DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1).
AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like
@include getopt.awk
in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path.
OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports.
EXAMPLES
cat << EOF > test.awk
@include getopt.awk
BEGIN {
while (getopt(ARGC, ARGV, "am:q") != -1)
...
}
EOF
igawk -f test.awk
SEE ALSO gawk(1)
Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995.
AUTHOR
Arnold Robbins (arnold@skeeve.com).
Free Software Foundation Nov 3 1999 IGAWK(1)