I have a large csv file that looks like this:
The 3rd field is a unix time stamp that I want to convert to human readable.
I wrote a bash script with this code:
IFS=$','
cat $1 | while read ID user DATE text flags read; do
echo -e "$ID,$user,$(date -d @$DATE),$text,$flags,$read... (3 Replies)
Below is the format of my file which consist of
1)BSB
2)BSB/ADS
3)CIB
4)CIB/CRH
5)CIB/DCC
6)CIB/EMD
7)CIB/GDSPresentation
8)CIB/HCH
9)CIB/HSM
10)CIB/MCH
11)CIB/RCH
12)COB
13)DCI
14)DIB
15)DIB/H2H
16)DIB/HotelSync
17)DIB/UADBA (11 Replies)
Hi,
Is there any short method to print from a particular field till another filed using awk?
Example File:
File1
====
1|2|acv|vbc|......|100|342
2|3|afg|nhj|.......|100|346
Expected output:
File2
====
acv|vbc|.....|100
afg|nhj|.....|100 (8 Replies)
Hi !
input:
111|222|333|aaa|bbb|ccc
999|888|777|nnn|kkk
444|666|555|eee|ttt|ooo|ppp
With awk, I am trying to change the FS "|" to "; " only from the 4th field until the end (the number of fields vary between records).
In order to get:
111|222|333|aaa; bbb; ccc
999|888|777|nnn; kkk... (1 Reply)
How do I do the product of nth filed just like sum. For sum I know like
awk '{ sum += $12 } END {printf "%.2f\n", sum}'
works as initial sum = 0.
But for product how do initialize the variable to 1? (2 Replies)
Hello
I was working on a script where the output of my file is
1234
4567
8973
43214
78965
I need the value in below format of this file.The nth field should have space instead of ,(comma)
1234,4567,8973,43214 78965
I tried the code but not working completely
xargs <temp_PP.7250... (3 Replies)
Using Awk, how can I achieve the following?
I have set of record numbers, for which, I have to replace the nth field with some values, say spaces.
Eg:
Set of Records : 4,9,10,55,89,etc
I have to change the 8th field of all the above set of records to spaces (10 spaces).
Its a delimited... (1 Reply)
I have posted this again as old post is closed and I am not able to reopen. so please consider this new post
Input File :
1,A,Completed,06.02_19.36,Jun 30 20:00
2,BBB,Failed,07.04_05.12,Jul 21 19:06
3,CCCCC,New,07.21_03.03,Jul 26 12:57
4,DDDDD,Pending,,
I wast output file as:
... (7 Replies)
Hi,
I have two (2) things that I want to do.
First is to change the date format that is in the nth field from MM/DD/YY to YY/MM/DD. Preferably, I wish I know how to make it a 4-digit year but I don't. Problem is I can only assume it is a 20 century
Second is somehow know how to figure out... (1 Reply)
For some reason I am having difficulty performing what should be a fairly easy task. I would like to print lines of a file that have a unique value in the first field. For example, I have a large data-set with the following excerpt:
PS003,001 MZMWR/ L-DWD// *
PS003,001... (4 Replies)
Discussion started by: jvoot
4 Replies
LEARN ABOUT DEBIAN
graphics::primitive::insets
Graphics::Primitive::Insets(3pm) User Contributed Perl Documentation Graphics::Primitive::Insets(3pm)NAME
Graphics::Primitive::Insets - Space between things
DESCRIPTION
Graphics::Primitive::Insets represents the amount of space that surrounds something. This object can be used to represent either padding
or margins (in the CSS sense, one being inside the bounding box, the other being outside)
SYNOPSIS
use Graphics::Primitive::Insets;
my $insets = Graphics::Primitive::Insets->new({
top => 5,
bottom => 5,
left => 5,
right => 5
});
METHODS
Constructor
new Creates a new Graphics::Primitive::Insets.
Instance Methods
as_array
Return these insets as an array in the form of top, right, bottom and left.
bottom
Set/Get the inset from the bottom.
equal_to
Determine if these Insets are equal to another.
left
Set/Get the inset from the left.
right
Set/Get the inset from the right.
top Set/Get the inset from the top.
zero
Sets all the insets (top, left, bottom, right) to 0.
AUTHOR
Cory Watson, "<gphat@cpan.org>"
SEE ALSO perl(1)COPYRIGHT & LICENSE
Copyright 2008-2010 by Cory G Watson.
This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
perl v5.12.3 2010-08-21 Graphics::Primitive::Insets(3pm)