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Full Discussion: Extract directory from full file name?
Top Forums UNIX for Dummies Questions & Answers Extract directory from full file name? Post 302727669 by jdorn001 on Tuesday 6th of November 2012 03:22:15 PM
Old 11-06-2012
Extract directory from full file name?
I think I know what this is doing, but the 'eval' is confusing

Code:
fname=$(echo ${lineItem} | awk 'BEGIN {FS=";"}{print $1}')
fname=${fname%%+([[:space:]])}
fname=${fname##+([[:space:]])}
eval "fname=${fname}"

The first line extracts the contents of the line preceeding the ";"
2nd & 3rd lines trim the value (I think .. not sure what the +([[:space:]]) does ..)
But what would be the purpose of the eval statement?
Last edited by joeyg; 11-07-2012 at 10:46 AM.. Reason: corrected spelling
 

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LEARN ABOUT CENTOS

zip_name_locate

ZIP_NAME_LOCATE(3)					     Library Functions Manual						ZIP_NAME_LOCATE(3)

NAME

       zip_name_locate - get index of file by name

LIBRARY

       libzip (-lzip)

SYNOPSIS

       #include <zip.h>

       int zip_name_locate(struct zip *archive, const char *fname, int flags);

DESCRIPTION

       The  zip_name_locate  function returns the index of the file named fname in archive.  If archive does not contain a file with that name, -1
       is returned.  The are specified by or'ing the following values, or 0 for none of them.

	      ZIP_FL_NOCASE  Ignore case distinctions.

	      ZIP_FL_NODIR   Ignore directory part of file name in archive.

RETURN VALUES

       zip_name_locate returns the index of the file named fname or -1, if archive does not contain an entry of that name.

ERRORS

       The zip_name_locate function fails and sets the error information to ZIP_ER_NOENT if no entry of the name fname is found  in  the  archive.
       If one of the arguments is invalid, the error information is set to ZIP_ER_INVAL.

SEE ALSO

       libzip(3), zip_get_name(3)

AUTHORS

       Dieter Baron <dillo@giga.or.at> and Thomas Klausner <tk@giga.or.at>

NiH								  October 4, 2006						ZIP_NAME_LOCATE(3)
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