Here's a very tight AND (hopefully) POSIX compliant version:
Code:
for i in *.sh; do echo "<#>"| cat $i - |awk -vfn="$i" '/.<#>/ {gsub("<#>",""); print fn, $0}'; done
a.sh apple
You need to find a "sentinel" string that doesn't interfere with your text.
Hi RudiC!
Thanks for posting this. As long as an incomplete line at the end of a file is no longer than {LINE_MAX}-4 bytes, this should work on any POSIX compliant system. This limit shouldn't be a problem given the way most of us write shell scripts and the submitter wanted this to process files matching the pattern *.sh.
I don't think we need to worry about this for this project, but note that the shell has no line length limit (other than available resources) when reading shell scripts. If a *.sh file has a valid shell script that contains one or more lines consisting of more than {LINE_MAX} bytes, the awk results would still be unspecified.
---------- Post updated at 15:36 ---------- Previous update was at 15:12 ----------
Quote:
Originally Posted by ctsgnb
Code:
for i in *.sh; do
[ -s "$i" ] && [ $(tail -1 $i | wc -l) = 0 ] && echo "$i has a missing '\n'"
done
and
Quote:
Originally Posted by Scrutinizer
Here is another one:
Code:
find . -type f -name "*.sh" |
while read f; do
[ $(wc -l < "$f") -ne $(grep -c '' "$f") ] && echo "$f"
done
Although both of these suggestions will probably work on many systems, they are not portable solutions. The standards say that the results are unspecified for both tail -n -1 "$i" and grep -c '' "$i" when $i names a non-empty file that does not have a <newline> character as the last byte of the file. (Note also that the 2008 revision of the POSIX standard and the Single UNIX Specification dropped the requirement to treat tail -1 file as a synonym for tail -n -1 file; this requirement was marked obsolete or deprecated in the 2004 revision of those standards.)
These 2 Users Gave Thanks to Don Cragun For This Post:
how to print any required line by its line no using awk and its NR variable
for eg:
------------
121343
adfdafd
21213sds
dafadfe432
adf.adf%adf
---------------
requied o/p if give num=3 it print:
21213sds
-------------------------------------- (2 Replies)
Ok I have a file with hundreds of lines, four columns, space delimited, TESTB.TXT for example
TESTB.TXT
---
AA ZZ 12 34
BB YY 56 78
CC XX 91 23
DD VV 45 67
---
I want a new file that has 7 columns, the first four are identical, and the next 3 are the last three of the next line...so... (5 Replies)
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for FILE in `cat list`; do
if ;
then
... (1 Reply)
Hi all,
I've a script that uses awk to parse the output of wget during a database update. The code I use is:
wget -c ftp://ftpsite/file 2>&1 | awk '/0%/ {print}'But this spits out each progress line on a new line:
37250K .......... .......... .......... .......... .......... 80% 10.9M 1s
... (2 Replies)
I can got the filename with this script. it's only show "-" in result.
cut -d , -f7 CSV_d.* | awk 'OFS=":"{print FILENAME,substr($1,1,8),substr($1,9,2),substr($1,11,2),substr($1,13,2)}' | sort |uniq (2 Replies)
Hi all,
From a while loop I am reading a sorted file where I want to print only the lines that have $1 match and $2 only when the difference from $2 from the previous line is > 30.
Input would be like ...
AN237 010 193019 0502 1 CSU Amoxycillin
AN237 080 ... (2 Replies)
Today I needed to take a look through a load of large backup files, so I wrote the following line to find them, order them by size, and print the file sizes in GB along with the filename. What happened was odd, the output was all as expected except for the first output line which had the filename... (4 Replies)
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caw-enabled ... (3 Replies)
I have files named with different prefixes. From each I want to extract the first line containing a specific string, and then print that line along with the prefix.
I've tried to do this with a while loop, but instead of printing the prefix I print the first line of the file twice.
Files:... (3 Replies)
Hi,
I have filename as:
010020001_S-FOR-Sort-SYEXC_20180109_062320_0100.x937
I need first 5 words of my filename along with the respective delimiters:
I tried this:
f=010020001_S-FOR-Sort-SYEXC_20180109_062320_0100.x937
echo $f | awk -F '' '{print $1$2$3$4$5}'
010020001SFORSortSYEXC
... (11 Replies)