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Top Forums Shell Programming and Scripting Help to get correct data using awk Post 302726385 by Jotne on Sunday 4th of November 2012 08:41:33 AM
Old 11-04-2012
I need to have the user as a variable.
This does not work:
Code:
user="test"
awk -v inp="$user" '{gsub("[|]"," ");if($1~/^inp$/) print $1,$5}' input

 

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giiQueryDeviceInfo(3)							GGI						     giiQueryDeviceInfo(3)

NAME
giiQueryDeviceInfo, giiQueryDeviceInfoByNumber - Get information about input sources SYNOPSIS
#include <ggi/gii.h>` int giiQueryDeviceInfo (gii_input_t inp, uint32_t origin, gii_cmddata_getdevinfo *info); int giiQueryDeviceInfoByNumber(gii_input_t inp, uint32_t number, uint32_t *origin, gii_cmddata_getdevinfo *info); DESCRIPTION
Though when using GII inputs the exact type of device is fully transparent to the program, information about the device that is actually attached to a given gii input and origin id can be queried, e.g. for configuration interfaces. For giiQueryDeviceInfo the parameters inp and origin select the input to query. This version is usually used, if you want to identify a device after getting an event from it. For giiQueryDeviceInfoByNumber the parameters inp and number select the input to query - origin gets set to the origin ID the queried device has. This version is used, when you want to query all known devices. The queried data is put into info. See gii_cmddata_getdevinfo(3) for the description of the structure. RETURN VALUE
Returns 0 on success (info is valid, then) or -1 otherwise. SEE ALSO
giiQueryValInfo(3) libgii-1.0.x 2006-12-30 giiQueryDeviceInfo(3)
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