Sponsored Content
Full Discussion: Function doesn't work
Top Forums Shell Programming and Scripting Function doesn't work Post 302725713 by ctsgnb on Friday 2nd of November 2012 01:58:45 PM
Old 11-02-2012
Note : when you are inside your function, "$1" refers to the first argument passed to your function (and not the first argument given to your shell script).

Instead of your function, you could go with :

Code:
echo "ibase=10;obase=16;$remainder" | bc


Last edited by ctsgnb; 11-02-2012 at 03:07 PM..
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Why doesn't this work?

cat .servers | while read LINE; do ssh jason@$LINE $1 done exit 1 ./command.ksh "ls -l ~jason" Why does this ONLY iterate on the first server in the list? It's not doing the command on all the servers in the list, what am I missing? Thanks! JP (2 Replies)
Discussion started by: jpeery
2 Replies

2. UNIX for Dummies Questions & Answers

Script doesn't work, but commands inside work

Howdie everyone... I have a shell script RemoveFiles.sh Inside this file, it only has two commands as below: rm -f ../../reportToday/temp/* rm -f ../../report/* My problem is that when i execute this script, nothing happened. Files remained unremoved. I don't see any error message as it... (2 Replies)
Discussion started by: cheongww
2 Replies

3. UNIX for Dummies Questions & Answers

FTP doesn't work

Hi! I have 2 servers. The firts has vsftpd server with this configuration: # Example config file /etc/vsftpd.conf # # The default compiled in settings are fairly paranoid. This sample file # loosens things up a bit, to make the ftp daemon more usable. # Please see vsftpd.conf.5 for all... (2 Replies)
Discussion started by: Torquemada
2 Replies

4. Shell Programming and Scripting

for loop doesn't work

I have a script which uses below for loop: for (( i = 0 ; i <= 5; i++ )) do echo "Welcome $i times" done But when I run the script, it gives error message: Syntex Error : Bad for loop variable Can anyone guide to run it? Thanks in advance. (10 Replies)
Discussion started by: naw_deepak
10 Replies

5. Shell Programming and Scripting

alias doesn't work

Hi I have put alias ll='ls -la' in .profile file but it doesn't work. On hand it works it looks like the .profile file is not beeing read. How to check whitch file is loaded? ,profile? .bash_profile? My system: SunOS mion 5.10 Generic Shell: /bin/pfksh Thanks (2 Replies)
Discussion started by: miojamo
2 Replies

6. Shell Programming and Scripting

echo doesn't work right

Hi,when I run my first shell script,I got something that doesn't work right. I wrote this code in the script. echo -e "Hello,World\a\n"But the screen print like this: -e Hello,World The "-e" wasn't supposed to be printed out. Can anyone help me out?:wall: Many thanks!:) (25 Replies)
Discussion started by: Demon
25 Replies

7. Shell Programming and Scripting

Why double quotation marks doesn't work in ksh function parameters passing?

I'm working on AIX 6, ksh shell. The parameters are some strings quotated by double quotation marks which from a file. They are quotated because there may be spaces in them. Example: "015607" "10" " " "A"I want to pass these parameters to a shell function by writing the following command: ... (4 Replies)
Discussion started by: Shimmey
4 Replies

8. UNIX for Dummies Questions & Answers

Why doesn't this work?

find . -name "05_scripts" -type d -exec mv -f {}/'*.aep\ Logs' {}/.LogFiles \; Returns this failure: mv: rename ./019_0120_WS_WH_gate_insideTEST/05_scripts/*.aep\ Logs to ./019_0120_WS_WH_gate_insideTEST/05_scripts/.LogFiles/*.aep\ Logs: No such file or directory I don't know why it's trying... (4 Replies)
Discussion started by: scribling
4 Replies

9. Shell Programming and Scripting

How come this if statement doesn't work?

greetings, the following code isn't working as i expect it to. the first dbl brackets do but the second set gets ignored. ie: if i'm on t70c6n229 it echoes "Something" and i expect it not to. what am i missing? if " ]] || " ]]; then echo "Something" fi thanx! (9 Replies)
Discussion started by: crimso
9 Replies

10. Shell Programming and Scripting

-ne 0 doesn't work -le does

Hi, I am using korn shell. until ] do echo "\$# = " $# echo "$1" shift done To the above script, I passed 2 parameters and the program control doesn't enter inside "until" loop. If I change it to until ] then it does work. Why numeric comparison is not working with -ne and works... (3 Replies)
Discussion started by: ab_2010
3 Replies
Devel::Refcount(3pm)					User Contributed Perl Documentation				      Devel::Refcount(3pm)

NAME
"Devel::Refcount" - obtain the REFCNT value of a referent SYNOPSIS
use Devel::Refcount qw( refcount ); my $anon = []; print "Anon ARRAY $anon has " . refcount($anon) . " reference "; my $otherref = $anon; print "Anon ARRAY $anon now has " . refcount($anon) . " references "; DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value. FUNCTIONS
$count = refcount($ref) Returns the reference count of the object being pointed to by $ref. COMPARISON WITH SvREFCNT This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed, whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH, CODE, GLOB and Regexp types) as well. Consider the following example program: use Devel::Peek qw( SvREFCNT ); use Devel::Refcount qw( refcount ); sub printcount { my $name = shift; printf "%30s has SvREFCNT=%d, refcount=%d ", $name, SvREFCNT($_[0]), refcount($_[0]); } my $var = []; printcount 'Initially, $var', $var; my $othervar = $var; printcount 'Before CODE ref, $var', $var; printcount '$othervar', $othervar; my $code = sub { undef $var }; printcount 'After CODE ref, $var', $var; printcount '$othervar', $othervar; This produces the output Initially, $var has SvREFCNT=1, refcount=1 Before CODE ref, $var has SvREFCNT=1, refcount=2 $othervar has SvREFCNT=1, refcount=2 After CODE ref, $var has SvREFCNT=2, refcount=2 $othervar has SvREFCNT=1, refcount=2 Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this case. Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it. After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the new anonymous CODE block. PURE-PERL FALLBACK An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in pure perl using the "B" module is used instead. This will behave identically, but is much slower. Rate pp xs pp 225985/s -- -66% xs 669570/s 196% -- SEE ALSO
o Test::Refcount - assert reference counts on objects AUTHOR
Paul Evans <leonerd@leonerd.org.uk> perl v5.14.2 2011-11-15 Devel::Refcount(3pm)
All times are GMT -4. The time now is 06:01 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy