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Full Discussion: Need to print between patterns AND a few lines before
Top Forums Shell Programming and Scripting Need to print between patterns AND a few lines before Post 302722337 by Finja on Friday 26th of October 2012 07:16:47 PM
Old 10-26-2012
Need to print between patterns AND a few lines before
I need to print out sections (varying numbers of lines) of a file between patterns. That alone is easy enough:
Code:
sed -n '/START/,/STOP/'

I also need the 3 lines BEFORE the start pattern. That alone is easy enough:
Code:
grep -B3 START

But I can't seem to combine the two so that I get everything between the patterns PLUS the 3 lines before the start of the pattern. I'm sure it's easy enough and I'm just not thinking it through, but it's been a long day. Help?
 

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LEARN ABOUT V7

zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)
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