Hi, all:
I've got two folders, folder A contains some image files (say, 100 files) in .jpg format;
folder B contains all description files (say, 500 files) in .txt format.
All image files in folder A are able to find their corresponding description files in folder B.
That is to say,... (3 Replies)
Guys, i need to replace a particular pattern in lots of files in a folder with another pattern . Is there any command line script I can use to do the functionality.
Eg: aalex > ls
green_1234_colour.max
red_1234_pen.max
yellow1234flower.max
Need to replace the 1234 in the file name with 9876... (4 Replies)
I splited a file into parts, then i wrote a script to convert the format of the file names to this: part1.dat part2.dat
but I wonder why part.dat is also created knowing that the k variable starts from 1
rm -f part*
$(split -b $1 file.1 part_)
set k = 1
for i in $(ls part_*)
do
mv -f... (1 Reply)
Hi,
I've got files with names like this :
_Some_Name_178_HD_.mp4
_Some_Name_-_496_Vost_SD_(720x400_XviD_MP3).avi
Goffytofansub_Some name 483_HD.avi
And iam trying to rename it with a regular pattern. My gola is this :
Ep 178.mp4
Ep 496.avi
Ep 483.avi
I've tried using sed with... (8 Replies)
Hi All,
I am trying to change the XML filename in a folder to the rootelement in the XML file.
Example: TestMsg2010-10-19_20_20_54.xml
<?xml version="1.0" encoding="utf-8" ?>
<R1Msg TimeStamp="2010-10-19T08:49:08.000000Z>
<TestRec>
<ID>1000</ID>
</TestRec>
</R1Msg>
Wanted to extract the... (8 Replies)
Hello,
I want to rename more than 100 files. These files have "?" in there existing file name but I want to rename files to there first part before "?" token. I have tried using for loop but it isn't working so help following is the sample filename and for loop that am trying to use:
example of... (3 Replies)
Hi, Hope someone can help... I'm pretty much new to unix and can only do basic commands.
I have an issue where by every day I need to schedule a job to look in a folder with a name format of .IP. will be different each day (when the day is over the folder extension changes), and rename any... (5 Replies)
Hi,
I have 1000 *.txt files in a folder and I would like to rename them data1.txt through data1000.txt. The order does not matter or the names of the initial input files. How would I go about doing that? Thanks! (1 Reply)
Hello All
A similar question like this was asked before but I need to change part of the question.
I've two folders, Folder A contains some image files in 150 subfolders;
Folder B contains text files in 350 subfolders.
All image files in Folder A have the same filename as the text... (5 Replies)
Entry level scripter. Any help appreciated.
for file in *; do rename '4321_' '' $file ; done
Doesn't work for files with spaces in between
FOr eg
4321_1004.dat is renamed to 1004.dat but
4321_1004 2008.dat stays the same (1 Reply)
Discussion started by: davnavin
1 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)