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Top Forums UNIX for Dummies Questions & Answers Need to get a loop variable from output of a command Post 302721545 by pat_pramod on Thursday 25th of October 2012 01:59:11 PM
Old 10-25-2012
Thanks a lot for quick reply, I got this.
Does it mean its not a nomber or I shoul correct the command by changing q with r or something.

Code:
echo "$i" | grep -q '^[0-9][0-9]*$' || { echo $i not a number ; exit ; }
grep: illegal option -- q
Usage: grep -hblcnsviw pattern file . . .
6 not a number


Last edited by Scott; 10-25-2012 at 03:32 PM.. Reason: Code tags
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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