10-24-2012
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10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hello,
Can you explain why in the first 2 commands the awk does not print anything? Is it looking of a specific format ?
Thanks.
$ echo 12a3 | awk '($1>=2) {print $1}' # prints nothing
$ echo 123a | awk '($1>=2) {print $1}' # prints nothing
$ echo a123 | awk '($1>=2) {print $1}'
a123... (1 Reply)
Discussion started by: majormark
1 Replies
2. Shell Programming and Scripting
I do not know how to do this unless I use a bunch of if statements. I need a script to replace numbers in each record in a file. I am really getting tangled in this web.
If a fieldA (19 positions) is greater than 14 digits, I have to change the data (resulting fieldA is fixed 19 postions).
If... (5 Replies)
Discussion started by: ski
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3. Shell Programming and Scripting
Hi Everyone,
# cat 1
1;2;3;4;5;6
1;2;3;4;5;
# awk -F ";" '$5 == "5"' 1
1;2;3;4;5;6
1;2;3;4;5;
but the output is should be just "1;2;3;4;5;6" means 1st condition: $5 is 5; 2nd condition: $6 is not empty, please advice. Thanks (2 Replies)
Discussion started by: jimmy_y
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4. Shell Programming and Scripting
Hi there,
I wanna define a variable 'tempbase'. Therefore I read a text file "base.out". "base.out" contains a list with four columns. 'tempbase' is the 4th entry in the line, where the first entry is equal to the predefined variable $orb1 and the second entry is equal to $orb2. I wrote the code... (2 Replies)
Discussion started by: friend
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5. Shell Programming and Scripting
Input File1
0BB2 2A11 Split,FriApr80625,1507_7RAID5
0BF6 2829 Synchronized,FriJan140653,1507_7RAID5
0BF6 282A Split,FriApr80625,1507_7RAID5
0C7C 199E Synchronized,FriJan140653,1507_7RAID5
0C7C 1BCC Split,FriApr80625,1507_7RAID5
0DCA 0A9B ... (12 Replies)
Discussion started by: greycells
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6. Shell Programming and Scripting
Hi there, here is my command
ssh host.local "/path/to/my/perscript/hostconfig.pl -s $HOST -d |awk '{if (\$4 > 120)print \"My error message\";exit}{s=0; for (i=1; i<=NF; i++) s++; if(s == 13) print \$3}'"
The problem is if conditional 1 is met (i.e $4 > 120), i don't see "My error message", the... (5 Replies)
Discussion started by: urello
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7. Shell Programming and Scripting
Hi All,
I have a file with below contents.
"en2"/10.185.81.0:cluster_interconnect,"en5"/10.185.81.0:cluster_interconnect,"en6"/169.181.146.0:public
I want to take the interface name from the file and convert it as ipaddress using ifconfig command get the output like below
en6 ->... (2 Replies)
Discussion started by: kamauv234
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8. Shell Programming and Scripting
Hello Friends,
I need to find some CDRs in production servers whose 1st field value and 2nd field value = 1 and 11th looks like 45.123... where there are more than 3 digits after comma.so i wrote a one liner, something like below but does not work, however when i used first and second conditions... (8 Replies)
Discussion started by: EAGL€
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9. Shell Programming and Scripting
awk 'BEGIN{
if('"$CATE"'<'"${WARN}"')
printf ("%s", "'"`Kfunc "" ; break`"'")
else if (('"${CATE}"'>='"${WARN}"') && ('"${CATE}"'<'"${CRIT}"'))
printf ("%s", "'"`Wfunc ""; break`"'")
else if ('"${CATE}"'>='"${CRIT}"')
printf... (6 Replies)
Discussion started by: SkySmart
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10. UNIX for Dummies Questions & Answers
hello gurus,
I want to use an associative array from a file to populate a field of another file, by matching several columns in order of priority. If the first column matches, then i dont want to match $2. Similarly I only want to match $3 when $1 and $2 are not in associative array.
For the... (6 Replies)
Discussion started by: ritakadm
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LEARN ABOUT DEBIAN
pam_rootok
PAM_ROOTOK(8) Linux-PAM Manual PAM_ROOTOK(8)
NAME
pam_rootok - Gain only root access
SYNOPSIS
pam_rootok.so [debug]
DESCRIPTION
pam_rootok is a PAM module that authenticates the user if their UID is 0. Applications that are created setuid-root generally retain the
UID of the user but run with the authority of an enhanced effective-UID. It is the real UID that is checked.
OPTIONS
debug
Print debug information.
MODULE TYPES PROVIDED
The auth, acct and password module types are provided.
RETURN VALUES
PAM_SUCCESS
The UID is 0.
PAM_AUTH_ERR
The UID is not 0.
EXAMPLES
In the case of the su(1) application the historical usage is to permit the superuser to adopt the identity of a lesser user without the use
of a password. To obtain this behavior with PAM the following pair of lines are needed for the corresponding entry in the /etc/pam.d/su
configuration file:
# su authentication. Root is granted access by default.
auth sufficient pam_rootok.so
auth required pam_unix.so
SEE ALSO
su(1), pam.conf(5), pam.d(5), pam(7)
AUTHOR
pam_rootok was written by Andrew G. Morgan, <morgan@kernel.org>.
Linux-PAM Manual 06/04/2011 PAM_ROOTOK(8)