Login or Register to Ask a Question and Join Our Community

Sponsored Content
Full Discussion: awk three conditions
Top Forums Shell Programming and Scripting awk three conditions Post 302720477 by MaindotC on Wednesday 24th of October 2012 09:21:23 AM
Old 10-24-2012
awk three conditions
I'm having a problem pulling UID's from data. The data outputs a user's UID in one of three ways:
Code:
1. Error User user_name already assigned with <UID>
2. Success <UID> reserved for user_name
3. <a load of crap because there was a db failure yet somehow the UID is still in there>

I typically used an awk statement to pull out the UID until item 3 started happening which I cannot control. If the first word of the output said "Success" then the UID was always in value 12. If the first word was "Error" then the UID was value 7, but I wouldn't bother checking for "Error" I would just look for "Success" and print value 12, else print value 7 (the additional sed is just for formatting):
Code:
awk '{if ($1 == "Success") {print $12} else print $7","$NF}' txt_file | cut -d, -f2,3 | sed 's/,//g'

So fundamentally all I'm trying to do is add 1 more condition to the awk statement. I tried inserting elif and else if and I keep getting syntax errors. How can I insert that third condition?

GNU Linux using ksh.
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

About awk conditions

Hello, Can you explain why in the first 2 commands the awk does not print anything? Is it looking of a specific format ? Thanks. $ echo 12a3 | awk '($1>=2) {print $1}' # prints nothing $ echo 123a | awk '($1>=2) {print $1}' # prints nothing $ echo a123 | awk '($1>=2) {print $1}' a123... (1 Reply)
Discussion started by: majormark
1 Replies

2. Shell Programming and Scripting

if, sed or awk with conditions

I do not know how to do this unless I use a bunch of if statements. I need a script to replace numbers in each record in a file. I am really getting tangled in this web. If a fieldA (19 positions) is greater than 14 digits, I have to change the data (resulting fieldA is fixed 19 postions). If... (5 Replies)
Discussion started by: ski
5 Replies

3. Shell Programming and Scripting

awk with two conditions

Hi Everyone, # cat 1 1;2;3;4;5;6 1;2;3;4;5; # awk -F ";" '$5 == "5"' 1 1;2;3;4;5;6 1;2;3;4;5; but the output is should be just "1;2;3;4;5;6" means 1st condition: $5 is 5; 2nd condition: $6 is not empty, please advice. Thanks (2 Replies)
Discussion started by: jimmy_y
2 Replies

4. Shell Programming and Scripting

awk line with two conditions

Hi there, I wanna define a variable 'tempbase'. Therefore I read a text file "base.out". "base.out" contains a list with four columns. 'tempbase' is the 4th entry in the line, where the first entry is equal to the predefined variable $orb1 and the second entry is equal to $orb2. I wrote the code... (2 Replies)
Discussion started by: friend
2 Replies

5. Shell Programming and Scripting

Checking conditions with AWK

Input File1 0BB2 2A11 Split,FriApr80625,1507_7RAID5 0BF6 2829 Synchronized,FriJan140653,1507_7RAID5 0BF6 282A Split,FriApr80625,1507_7RAID5 0C7C 199E Synchronized,FriJan140653,1507_7RAID5 0C7C 1BCC Split,FriApr80625,1507_7RAID5 0DCA 0A9B ... (12 Replies)
Discussion started by: greycells
12 Replies

6. Shell Programming and Scripting

Conditions in awk

Hi there, here is my command ssh host.local "/path/to/my/perscript/hostconfig.pl -s $HOST -d |awk '{if (\$4 > 120)print \"My error message\";exit}{s=0; for (i=1; i<=NF; i++) s++; if(s == 13) print \$3}'" The problem is if conditional 1 is met (i.e $4 > 120), i don't see "My error message", the... (5 Replies)
Discussion started by: urello
5 Replies

7. Shell Programming and Scripting

awk with conditions

Hi All, I have a file with below contents. "en2"/10.185.81.0:cluster_interconnect,"en5"/10.185.81.0:cluster_interconnect,"en6"/169.181.146.0:public I want to take the interface name from the file and convert it as ipaddress using ifconfig command get the output like below en6 ->... (2 Replies)
Discussion started by: kamauv234
2 Replies

8. Shell Programming and Scripting

If conditions in awk

Hello Friends, I need to find some CDRs in production servers whose 1st field value and 2nd field value = 1 and 11th looks like 45.123... where there are more than 3 digits after comma.so i wrote a one liner, something like below but does not work, however when i used first and second conditions... (8 Replies)
Discussion started by: EAGL€
8 Replies

9. Shell Programming and Scripting

awk problems - awk ignores conditions

awk 'BEGIN{ if('"$CATE"'<'"${WARN}"') printf ("%s", "'"`Kfunc "" ; break`"'") else if (('"${CATE}"'>='"${WARN}"') && ('"${CATE}"'<'"${CRIT}"')) printf ("%s", "'"`Wfunc ""; break`"'") else if ('"${CATE}"'>='"${CRIT}"') printf... (6 Replies)
Discussion started by: SkySmart
6 Replies

10. UNIX for Dummies Questions & Answers

Sequence of conditions awk

hello gurus, I want to use an associative array from a file to populate a field of another file, by matching several columns in order of priority. If the first column matches, then i dont want to match $2. Similarly I only want to match $3 when $1 and $2 are not in associative array. For the... (6 Replies)
Discussion started by: ritakadm
6 Replies

LEARN ABOUT LINUX

pam_rootok

PAM_ROOTOK(8)							 Linux-PAM Manual						     PAM_ROOTOK(8)

NAME

       pam_rootok - Gain only root access

SYNOPSIS

       pam_rootok.so [debug]

DESCRIPTION

       pam_rootok is a PAM module that authenticates the user if their UID is 0. Applications that are created setuid-root generally retain the
       UID of the user but run with the authority of an enhanced effective-UID. It is the real UID that is checked.

OPTIONS

       debug
	   Print debug information.

MODULE TYPES PROVIDED

       The auth, acct and password module types are provided.

RETURN VALUES

       PAM_SUCCESS
	   The UID is 0.

       PAM_AUTH_ERR
	   The UID is not 0.

EXAMPLES

       In the case of the su(1) application the historical usage is to permit the superuser to adopt the identity of a lesser user without the use
       of a password. To obtain this behavior with PAM the following pair of lines are needed for the corresponding entry in the /etc/pam.d/su
       configuration file:

	   # su authentication. Root is granted access by default.
	   auth  sufficient   pam_rootok.so
	   auth  required     pam_unix.so

SEE ALSO

       su(1), pam.conf(5), pam.d(5), pam(7)

AUTHOR

       pam_rootok was written by Andrew G. Morgan, <morgan@kernel.org>.

Linux-PAM Manual						    06/04/2011							     PAM_ROOTOK(8)
All times are GMT -4. The time now is 06:23 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy