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Top Forums Shell Programming and Scripting Get 20% of lines in File randomly Post 302719111 by Lem on Monday 22nd of October 2012 05:34:32 AM
Old 10-22-2012
Quote:
Originally Posted by chercheur857
My question please how can i eliminate 50 an 51 , i mean i'd like 25% of this list other than this two lines 50 and 51, and i'd like to specify it in the command like that
Code:
./program Myfile 10 50 51

Have you an idea please ?
Thank you so much for help Smilie
Code:
#!/bin/bash

inputfile="/tmp/buddyfile"
cp "$1" $inputfile
(( $# < 3 )) || {
        string="-${3}$"
        for ((a=4;a<=$#;a++)); do
                string+="\|-${!a}$"
        done
        sed -i "/$string/d" $inputfile; }

range=$(wc -l $inputfile | cut -d " " -f1)
(( $range > 32768 )) && exit              ### max number of lines for this script: 32768
percent=$2                                ### set this  as you like, [1-100]
(( 0 < $2 )) && (( $2 < 101 )) || exit
lim=$(( $range * $percent / 100 ))
for ((i=0;i<lim;i++)); do
        num=$(( $RANDOM % $range + 1 ));
        arr[$i]=$num;
        for ((j=0;j<i;j++)); do
                (( ${arr[$j]} == $num )) && {
                        let i--
                        break; }
        done
done

for linenum in "${arr[@]}"; do
        line=$(sed -n "$linenum p" $inputfile)
        ### your stuff here, for example: ###
        echo "$linenum"$'\t'"### $line"
done

exit 0

Changes are in bold. I didn't test it, but it should work.

Of course if 50, 51 and friends are true line numbers counting from 1 (first line) onwards, we can simplify the new part of the script.

Beware: if you have a file of 100 lines, and you exclude 40 lines, and you want 30% of the lines, you'll get 30% of the remaining 60 lines, so you'll get 18 lines. Is this right for you, or do you still want 30 lines among the 60 remaining lines?
--
Bye

Last edited by Lem; 10-22-2012 at 06:43 AM..
This User Gave Thanks to Lem For This Post:
 

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PAPS(1) 						      General Commands Manual							   PAPS(1)

NAME
paps - UTF-8 to PostScript converter using Pango SYNOPSIS
paps [options] files... DESCRIPTION
paps reads a UTF-8 encoded file and generates a PostScript language rendering of the file. The rendering is done by creating outline curves through the pango ft2 backend. OPTIONS
These programs follow the usual GNU command line syntax, with long options starting with two dashes (`-'). A summary of options is included below. --landscape Landscape output. Default is portrait. --columns=cl Number of columns output. Default is 1. Please notice this option isn't related to the terminal length as in a "80 culums terminal". --font=desc Set the font description. Default is Monospace 12. --rtl Do right to left (RTL) layout. --paper ps Choose paper size. Known paper sizes are legal, letter and A4. Default is A4. Postscript points Each postscript point equals to 1/72 of an inch. 36 points are 1/2 of an inch. --bottom-margin=bm Set bottom margin. Default is 36 postscript points. --top-margin=tm Set top margin. Default is 36 postscript points. --left-margin=lm Set left margin. Default is 36 postscript points. --right-margin=rm Set right margin. Default is 36 postscript points. --gutter-width=gw Set gutter width. Default is 40 postscript points. --help Show summary of options. --header Draw page header for each page. --markup Interpret the text as pango markup. --lpi Set the lines per inch. This determines the line spacing. --cpi Set the characters per inch. This is an alternative method of specifying the font size. --stretch-chars Indicates that characters should be stretched in the y-direction to fill up their vertical space. This is similar to the texttops behaviour. AUTHOR
paps was written by Dov Grobgeld <dov.grobgeld@gmail.com>. This manual page was written by Lior Kaplan <kaplan@debian.org>, for the Debian project (but may be used by others). April 17, 2006 PAPS(1)
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