Hi List,
Is it possible to pass one argument to a shell program
eg) there is a shell program abc which takes one arguments
abc one
Due to some reasons I pass
abc one two
Now one,two must be considered as "one" argument to the shell programs. Any suggestions,hints are welcome.
... (3 Replies)
Can someone help me to understand this part of code?
/bin/nawk -f awkfile file1 file2
I know awkfile is the one with awk script.
file1 is source file that needs to be processed.
What is file2 two?
Thanks for your help! (4 Replies)
In DDD debugger, where to set the the arguments for main program?
For example: ./myExe "argv1" "argv2" -> where to set "argv1" & "argv2" ?
Thanks! (2 Replies)
I have a shell script that is attempting to call a c program.
I call the c program with ./dictool
dictool accepts arguments at runtime. It works by prompting the user for various commands, acting on those commands, spitting out an output, and then prompting for more commands.
My question is,... (1 Reply)
I have the following piece of code. Currently the command line arguments are passed as shown below using the "= "sign. I capture the name of the argument, for example vmod and it's corresponding user parameter which is jcdint-z30.cmd.
./raytrac vmod=jcdint-z30.cmd srFile=jcdint.sr
Now I want... (12 Replies)
Hello,
The arguments are strings. In my code I need them to be a different type, I do the cast but it is not feasible ...
Have you any idea?
Thank you (8 Replies)
I want to write a C++ program that uses a class to do some calculations.
I pass arguments to the program, some of which are used to set up class members. A class function will then perform the necessary calculations.
I am wondering how I should pass the arguments from the program to set the... (2 Replies)
Dear Users,
I have installed a standalone program to do multiple sequence alignment which takes user parameters to run the program. I have multiple sequence files and want to automate this process through a bash script. I have tried to write a small bash code but its throwing errors.
Kindly... (13 Replies)
#!/bin/awk -f
BEGIN {
FS=":";
}
{
if ( $7 == "" ) {
print $1 ": no password!";
}
}
I want to execute this program for a particular user to check for his password from the file /etc/passwd (as the input file) and the user details to be given... (1 Reply)
Discussion started by: sri.phani
1 Replies
LEARN ABOUT PHP
datefmt_set_pattern
DATEFMT_SET_PATTERN(3) 1 DATEFMT_SET_PATTERN(3)IntlDateFormatter::setPattern - Set the pattern used for the IntlDateFormatter
Object oriented style
SYNOPSIS
public bool IntlDateFormatter::setPattern (string $pattern)
DESCRIPTION
Procedural style
bool datefmt_set_pattern (IntlDateFormatter $fmt, string $pattern)
Set the pattern used for the IntlDateFormatter.
PARAMETERS
o $fmt
- The formatter resource.
o $pattern
- New pattern string to use. Possible patterns are documented at http://userguide.icu-project.org/formatparse/datetime.
RETURN VALUES
Returns TRUE on success or FALSE on failure. Bad formatstrings are usually the cause of the failure.
EXAMPLES
Example #1
datefmt_set_pattern(3) example
<?php
$fmt = datefmt_create(
'en_US',
IntlDateFormatter::FULL,IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'MM/dd/yyyy'
);
echo 'pattern of the formatter is : ' . datefmt_get_pattern($fmt);
echo 'First Formatted output with pattern is ' . datefmt_format($fmt, 0);
datefmt_set_pattern($fmt, 'yyyymmdd hh:mm:ss z');
echo 'Now pattern of the formatter is : ' . datefmt_get_pattern($fmt);
echo 'Second Formatted output with pattern is ' . datefmt_format($fmt, 0);
?>
Example #2
OO example
<?php
$fmt = new IntlDateFormatter(
'en_US',
IntlDateFormatter::FULL,IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'MM/dd/yyyy'
);
echo 'pattern of the formatter is : ' . $fmt->getPattern();
echo 'First Formatted output is ' . $fmt->format(0);
$fmt->setPattern('yyyymmdd hh:mm:ss z');
echo 'Now pattern of the formatter is : ' . $fmt->getPattern();
echo 'Second Formatted output is ' . $fmt->format(0);
?>
The above example will output:
pattern of the formatter is : MM/dd/yyyy
First Formatted output with pattern is 12/31/1969
Now pattern of the formatter is : yyyymmdd hh:mm:ss z
Second Formatted output with pattern is 19690031 04:00:00 PST
SEE ALSO datefmt_get_pattern(3), datefmt_create(3).
PHP Documentation Group DATEFMT_SET_PATTERN(3)