10-16-2012
Quote:
Originally Posted by
babom
is there any workaround for this issue...
Have you tried using awk..?
Please provide your input and desired output.
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Folks,
Is there a simple way to replace one digit by two digit using sed.
Example,
mydigit1918_2006_8_8_lag1.csv should be
mydigit1918_2006_08_08_lag01.csv.
I tried this way, but doesn't work.
echo mydigit1989_2006_8_8_lag1.csv|sed 's/]/0]/'
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2. Shell Programming and Scripting
if abc.sh is
192.168.1.41
then the output that i get is v5c01
my code is
sed 's/192.168.1.4/v5c0/g
s/192.168.1.41/acc1/g' abc.sh 2>&1 | tee abc.sh
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comment on this: 3900302
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3900302
12
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Bendicks
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Ben
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3840 3841 3842 Dav Thun Tax
Cahn 146; Dav.
3855 3853 3861 3862 Dav Thun Tax
2780 Karl VI.,
3873 3872 3872 Dav Thun Tax
3894 3893 3897 3899 Dav Thun Tax
403; Thun 282.
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Hi Guys.
My Input:
ABCD 12 00 KL
ABCD 12 08 DL
ABCD 12 10 KK
ABCD 12 04 LL
ABCD 13 00 LP
ABCD 13 1O LS
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ABCD 12 8 DL
ABCD 12 10 KK
ABCD 12 4 LL
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The intended result should be :
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