10-15-2012
How to get top level parent directory
Hi All,
I have a directory like this: /u01/app/oracle/11gSE1/11gR203
How do i get the top level directory /u01 from this? Tried dirname and basename but dint help. I can this using echo $ORACLE_HOME | awk -F"/" '{print "/"$2}'. But I am trying to find out if there is a better way of doing it other than using awk. Thanks in advance.
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LEARN ABOUT FREEBSD
dirname
BASENAME(1) BSD General Commands Manual BASENAME(1)
NAME
basename, dirname -- return filename or directory portion of pathname
SYNOPSIS
basename string [suffix]
basename [-a] [-s suffix] string [...]
dirname string [...]
DESCRIPTION
The basename utility deletes any prefix ending with the last slash '/' character present in string (after first stripping trailing slashes),
and a suffix, if given. The suffix is not stripped if it is identical to the remaining characters in string. The resulting filename is
written to the standard output. A non-existent suffix is ignored. If -a is specified, then every argument is treated as a string as if
basename were invoked with just one argument. If -s is specified, then the suffix is taken as its argument, and all other arguments are
treated as a string.
The dirname utility deletes the filename portion, beginning with the last slash '/' character to the end of string (after first stripping
trailing slashes), and writes the result to the standard output.
EXIT STATUS
The basename and dirname utilities exit 0 on success, and >0 if an error occurs.
EXAMPLES
The following line sets the shell variable FOO to /usr/bin.
FOO=`dirname /usr/bin/trail`
SEE ALSO
csh(1), sh(1), basename(3), dirname(3)
STANDARDS
The basename and dirname utilities are expected to be IEEE Std 1003.2 (``POSIX.2'') compatible.
BSD
April 18, 1994 BSD