Transpose timestamp based on column values and calculate time difference
Hello Expert,
I need to transpose Date-Timestamp based on same column values and calculate time difference. The input file would be as below and required output is mentioned in the bottom
Hi,
Please help me in calculating the time difference between below mentioned timestamps.
a=07/17/2007 02:20:00 AM MST
b=07/17/2007 02:07:46 AM MST
Thanks (2 Replies)
Hi All,
I've written a script which reads all the systems backup information and saves it in a log file.
ssh -l ora${sid} ${primaryhost} "tail -1 /oracle/$ORACLE_SID/sapbackup/back$ORACLE_SID.log" | awk '{print $3,$4,$5,$6}' >> ${RESULTFILE}
The output comes as below:
2008-09-30 06.00.01... (2 Replies)
Hello All,
I have a problem calculating the time difference between start and end timings...!
the timings are given by 24hr format..
Start Date : 08/05/10 12:55
End Date : 08/09/10 06:50
above values are in mm/dd/yy hh:mm format.
Now the thing is, 7th(08/07/10) and... (16 Replies)
Hi,
I have a file containing timestamps (at micro-seconds granularity). It looks like the following:
06:49:42.383818
06:49:42.390190
06:49:42.392308
06:49:42.392712
06:49:42.393437
06:49:42.393960
06:49:42.402115
Now I need a sed/awk script to take the difference of two successive... (2 Replies)
Hello,
I'm trying to create a shell script (#!/bin/sh) which should tell me the age of a file in minutes...
I have a process, which delivers me all 15 minutes a new file and I want to have a monitoring script, which sends me an email, if the present file is older than 20 minutes.
To do... (10 Replies)
Hi All,
I'm looking for a script which can transpose field names from column headers to values in one column.
for example, the input is:
IDa;IDb;IDc;PARAM1;PARAM2;PARAM3;
a;b;c;p1val;p2val;p3val;
d;e;f;p4val;p5val;p6val;
g;h;i;p7val;p8val;p9val;
into the output like this:
... (6 Replies)
Hi Friends,
Require a quick help to write the difference between 2 timestamps based on a unique column value:
Input file:
08/23/2012 12:36:09,JOB_5340,08/23/2012 12:36:14,JOB_5340
08/23/2012 12:36:22,JOB_5350,08/23/2012 12:36:26,JOB_5350
08/23/2012 13:08:51,JOB_5360,08/23/2012... (4 Replies)
I have time in a file in HH:MM:SS format as it contents(its not the file creation time). i need this to be converted to epoch time or time since 1970. The time is written into that file by a script, which i cannot modify. Im using AIX machine
$ cat abc.txt
10:29:34 (2 Replies)
Gents,
Transpose from row to column, taking in consideration the first column, which contends the date.
Input file
72918,111000009,111000009,111000009,111000009,111000009,111000009,111000009,111000009,111000009
72918,2356,2357,2358,2359,2360,2361,2362,2363,2364
72918,0,0,0,0,0,0,0,0,0... (12 Replies)
Discussion started by: jiam912
12 Replies
LEARN ABOUT REDHAT
dtptrs
DTPTRS(l) ) DTPTRS(l)
NAME
DTPTRS - solve a triangular system of the form A * X = B or A**T * X = B,
SYNOPSIS
SUBROUTINE DTPTRS( UPLO, TRANS, DIAG, N, NRHS, AP, B, LDB, INFO )
CHARACTER DIAG, TRANS, UPLO
INTEGER INFO, LDB, N, NRHS
DOUBLE PRECISION AP( * ), B( LDB, * )
PURPOSE
DTPTRS solves a triangular system of the form A * X = B or A**T * X = B, where A is a triangular matrix of order N stored in packed format,
and B is an N-by-NRHS matrix. A check is made to verify that A is nonsingular.
ARGUMENTS
UPLO (input) CHARACTER*1
= 'U': A is upper triangular;
= 'L': A is lower triangular.
TRANS (input) CHARACTER*1
Specifies the form of the system of equations:
= 'N': A * X = B (No transpose)
= 'T': A**T * X = B (Transpose)
= 'C': A**H * X = B (Conjugate transpose = Transpose)
DIAG (input) CHARACTER*1
= 'N': A is non-unit triangular;
= 'U': A is unit triangular.
N (input) INTEGER
The order of the matrix A. N >= 0.
NRHS (input) INTEGER
The number of right hand sides, i.e., the number of columns of the matrix B. NRHS >= 0.
AP (input) DOUBLE PRECISION array, dimension (N*(N+1)/2)
The upper or lower triangular matrix A, packed columnwise in a linear array. The j-th column of A is stored in the array AP as
follows: if UPLO = 'U', AP(i + (j-1)*j/2) = A(i,j) for 1<=i<=j; if UPLO = 'L', AP(i + (j-1)*(2*n-j)/2) = A(i,j) for j<=i<=n.
B (input/output) DOUBLE PRECISION array, dimension (LDB,NRHS)
On entry, the right hand side matrix B. On exit, if INFO = 0, the solution matrix X.
LDB (input) INTEGER
The leading dimension of the array B. LDB >= max(1,N).
INFO (output) INTEGER
= 0: successful exit
< 0: if INFO = -i, the i-th argument had an illegal value
> 0: if INFO = i, the i-th diagonal element of A is zero, indicating that the matrix is singular and the solutions X have not been
computed.
LAPACK version 3.0 15 June 2000 DTPTRS(l)