10-14-2012
Quote:
Originally Posted by
Don Cragun
On the machines most of us work on, floating point numbers are represented as x*2^y or x*16^y rather than x*10^y
I know how it works. It wasn't too relevant to the example. The point is it uses an exponent, it's not stored literally.
Quote:
but .5 is exactly representable in any of them.
0.5 is. Anything else .5 depends.
Quote:
As pointed out by Scrutinizer, the real answer lies in the rounding mode being used by whatever function is converting the internal floating point value to a printable decimal representation of that value.
Yes, which I pointed out most generally don't. ksh93 would be an exception.
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floor(3m) floor(3m)
Name
floor, ffloor, fabs, ceil, ceil, trunc, ftrunc, fmod, rint - floor, absolute value, ceiling, truncation, floating point remainder and
round-to-nearest functions
Syntax
#include <math.h>
double floor(x)
double x;
float ffloor(x)
float x;
double ceil(x)
double x;
float fceil(x)
float x;
double trunc(x)
double x;
float ftrunc(x)
float x;
double fabs(x)
double x;
double fmod (x, y)
double x, y;
double rint(x)
double x;
Description
The and routines return the largest integer which is not greater than x for double and float data types, respectively.
The and routines return the smallest integer which is not less than x for double and float data types, respectively.
The and routines return the integer (represented as a floating-point number) of x with the fractional bits truncated for double and float
data types respectively.
The routine returns the absolute value |x|.
The routine returns the floating point remainder of the division of x by y: zero if y is zero or if x/y would overflow; otherwise the num-
ber f with the same sign as x, such that x = iy + f for some integer i, and |f| < |y|.
The routine returns the integer (represented as a double precision number) nearest x in the direction of the prevailing rounding mode.
In the default rounding mode, to nearest, is the integer nearest x with the additional stipulation that if |rint(x)-x|=1/2 then is even.
Other rounding modes can make act like or or round towards zero.
Another way to obtain an integer near x is to declare (in C)
double x; int k; k = x;
The C compiler rounds x towards 0 to get the integer k. Also note that, if x is larger than k can accommodate, the value of k and the
presence or absence of an integer overflow are hard to predict.
The routine is in libc.a rather than libm.a.
See Also
abs(3), ieee(3m), math(3m)
RISC floor(3m)