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Top Forums Shell Programming and Scripting Help me pls : splitting single file in unix into different files based on data Post 302715259 by Ravindra Swan on Sunday 14th of October 2012 08:57:26 AM
Old 10-14-2012
Bug Clarification

For suppose let us assume we have :
Quote:
Input_File1
Join2
Output_File3
reformat4
Reformat5
PKS6
Lookup7
Input_File8
now i need

Quote:
Input_File1
Input_File1_f
Join2
Output_File3
reformat4
Reformat5
PKS6
Lookup7
Input_File8
Input_File8_f

Quote:
where cat Input_File1_f might be giving :

Input_File1
Reformat5
Lookup7
Output_File3
and
Quote:
cat Input_File8_f might be giving :

Input_File1
Reformat5
PKS6
reformat4
Output_File3

As many as i have Input_Files corresponding Input_Files_f files must be generated and they must contain the file names where they had flow(i guess u already got a picture of flow +5000 , -5000) and also for all the Input_Files_f, First line will be the corresponding Input_file name and last line will be Output_File.

Now is it clear??
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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